[#858] Energy per kilo (Part 1) Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGS=42000 km. Consider the mechanical energy of the same body on Earth at the South pole, at re=6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator is in orbit, the object at the Pole is not in orbit.) G=6.67×10−11 Nm2kg−2, and the mass of the Earth is M=5.97×1024 kg What is the difference in the mechanical energy per kilogram between the two? E =E= ___ MJ.kg−1 (to two significant figures, don't use scientific notation)
[#858] Energy per kilo (Part 1)
Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGS=42000 km.
Consider the mechanical energy of the same body on Earth at the South pole, at re=6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator is in orbit, the object at the Pole is not in orbit.)
G=6.67×10−11 Nm2kg−2, and the mass of the Earth is M=5.97×1024 kg
What is the difference in the mechanical energy per kilogram between the two?
E =E= ___ MJ.kg−1 (to two significant figures, don't use scientific notation)
[#859] Energy per kilo (Part 2)
Consider the mechanical energy of a body at rest on the ground at the Earth's equator, at re=6400 km
Consider the mechanical energy of the same body at rest on the ground at the South pole, at re=6400 km. For this problem, we consider the Earth to be spherical.
(Remember, the object at the equator traces a circular path, the object at the Pole does not.)
G=6.67×10−11 Nm2kg−2, and the mass of the Earth is M=5.97×1024 kg
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How much more mechanical energy per kilogram does an object on the ground at the Equator than on the ground at the Pole?
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E =E= ___MJ.kg−1 . (2 sig figs, do not use scientific notation)
I've been trying to solve this for hours and I can't seem to get it right lol, pls help y'all
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