8:45 PM +51 969 383 276 Hoy, 7:38 p. m. 9-15. Determine the vertical displacement of joint C of the truss. Each member has a cross-sectional area of A = 300 mm². E=200 GPa. Use the method of virtual work. H Vo 4G LTE 3 D 4 m 4 m +4m + 4 m 3 kN 3 kN 4 kN The virtual and real forces in each member are shown in Fig. a and b respectively. Member n(kN) N(kN) L(m) nNL(kN2 m) AB 0.6667 6.667 4 17.78 DE 0.6667 6.667 4 17.78 BC 1.333 9.333 4 49.78 CD 1.333 9.333 4 49.78 АН -0.8333 -8.333 5 34.72 EF -0.8333 -8.333 5 34.72 BH 0.5 5 3 7.50 DF 0.5 5 3 7.50 BG -0.8333 -3.333 5 13.89 DG -0.8333 -3.333 5 13.89 GH -0.6667 -6.6667 4 17.78 FG -0.6667 -6.6667 4 17.78 CG 1 4 3 12.00 Σ = 294.89 3 m
8:45 PM +51 969 383 276 Hoy, 7:38 p. m. 9-15. Determine the vertical displacement of joint C of the truss. Each member has a cross-sectional area of A = 300 mm². E=200 GPa. Use the method of virtual work. H Vo 4G LTE 3 D 4 m 4 m +4m + 4 m 3 kN 3 kN 4 kN The virtual and real forces in each member are shown in Fig. a and b respectively. Member n(kN) N(kN) L(m) nNL(kN2 m) AB 0.6667 6.667 4 17.78 DE 0.6667 6.667 4 17.78 BC 1.333 9.333 4 49.78 CD 1.333 9.333 4 49.78 АН -0.8333 -8.333 5 34.72 EF -0.8333 -8.333 5 34.72 BH 0.5 5 3 7.50 DF 0.5 5 3 7.50 BG -0.8333 -3.333 5 13.89 DG -0.8333 -3.333 5 13.89 GH -0.6667 -6.6667 4 17.78 FG -0.6667 -6.6667 4 17.78 CG 1 4 3 12.00 Σ = 294.89 3 m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:8:45 PM
+51 969 383 276
Hoy, 7:38 p. m.
9-15. Determine the vertical displacement of joint C of the
truss. Each member has a cross-sectional area of A = 300 mm².
E=200 GPa. Use the method of virtual work.
H
Vo
4G
LTE
3
D
4 m
4 m
+4m
+
4 m
3 kN
3 kN
4 kN
The virtual and real forces in each member are shown in Fig. a and b respectively.
Member
n(kN)
N(kN)
L(m)
nNL(kN2 m)
AB
0.6667
6.667
4
17.78
DE
0.6667
6.667
4
17.78
BC
1.333
9.333
4
49.78
CD
1.333
9.333
4
49.78
АН
-0.8333
-8.333
5
34.72
EF
-0.8333
-8.333
5
34.72
BH
0.5
5
3
7.50
DF
0.5
5
3
7.50
BG
-0.8333
-3.333
5
13.89
DG
-0.8333
-3.333
5
13.89
GH
-0.6667
-6.6667
4
17.78
FG
-0.6667
-6.6667
4
17.78
CG
1
4
3
12.00
Σ = 294.89
3 m
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