800 g of ice at -10C is heatedto steam at 115C using a heater,rated 1500 W. Compute the total time required to heat the ice to steam  Given ice=2100 J/KJ water=4186 J/kg  steam= 2000 J/kg  Lf= 3.33 x 10^5 J/Kg Lv = 22.6 x 10^5 J/Kg

icon
Related questions
Question

800 g of ice at -10C is heatedto steam at 115C using a heater,rated 1500 W. Compute the total time required to heat the ice to steam 

Given ice=2100 J/KJ
water=4186 J/kg 
steam= 2000 J/kg 

Lf= 3.33 x 10^5 J/Kg
Lv = 22.6 x 10^5 J/Kg

 

 

Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer