8.9.7 2f (x) – 3f(;) = x² Note that for this equation, the function values involve both x and its recip- rocal, x-1, i.e., 1 2f (x) – 3f = 22. (8.411) Replacing x by x -1 produces the equation 21 () – 1 E) - 3f (x) = (8.412) If equations (8.411) and (8.412) are multiplied, respectively, by 2 and 3, and added, then we have 3 -5f(x) = 2x2 + %3D and - (6)-- (6) 뉴 (): 1 f (x) = (8.413)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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8.9.7 2f(x) – 3f() = x²
Note that for this equation, the function values involve both x and its recip-
rocal, x-1, i.e.,
()
2f(x) – 3f
(8.411)
Replacing x by x-1 produces the equation
1
2f
-) - 3f (x)
x2
(8.412)
If equations (8.411) and (8.412) are multiplied, respectively, by 2 and 3, and
added, then we have
-5f(x) = 2x2 +
x2
and
(1)-² - (;) -
f (x) =
(8.413)
x2
Transcribed Image Text:8.9.7 2f(x) – 3f() = x² Note that for this equation, the function values involve both x and its recip- rocal, x-1, i.e., () 2f(x) – 3f (8.411) Replacing x by x-1 produces the equation 1 2f -) - 3f (x) x2 (8.412) If equations (8.411) and (8.412) are multiplied, respectively, by 2 and 3, and added, then we have -5f(x) = 2x2 + x2 and (1)-² - (;) - f (x) = (8.413) x2
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