(8.2)Which of the following occurs as the wavelength of a photon increases? O None of the above occurs as the wavelength of a photon increases. O The frequency decreases. O The speed decreases. O The energy increases.
(8.2)Which of the following occurs as the wavelength of a photon increases? O None of the above occurs as the wavelength of a photon increases. O The frequency decreases. O The speed decreases. O The energy increases.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:### Photon Wavelength and Corresponding Effects
**Question (8.2): Which of the following occurs as the wavelength of a photon increases?**
1. ⬜ None of the above occurs as the wavelength of a photon increases.
2. ⬜ The frequency decreases.
3. ⬜ The speed decreases.
4. ⬜ The energy increases.
**Explanation:**
This question is designed to test your understanding of the relationship between the wavelength, frequency, speed, and energy of photons. Let's explore each option to determine the correct answer:
- **None of the above occurs as the wavelength of a photon increases:** This option implies that no significant changes occur with an increase in the wavelength of a photon. However, scientific principles indicate otherwise.
- **The frequency decreases:** According to the wave equation \( c = \lambda \nu \) (where \( c \) is the speed of light, \( \lambda \) is the wavelength, and \( \nu \) is the frequency), if \( \lambda \) (wavelength) increases, then \( \nu \) (frequency) must decrease to keep the equation balanced, assuming the speed of light is constant in vacuum.
- **The speed decreases:** The speed of a photon, particularly in a vacuum, is a constant (approximately \( 3 \times 10^8 \) meters per second). Therefore, the speed does not decrease with an increase in wavelength.
- **The energy increases:** The energy of a photon can be expressed by the equation \( E = h\nu \) (where \( E \) is energy, \( h \) is Planck's constant, and \( \nu \) is frequency). Because frequency decreases with increasing wavelength, the energy of the photon also decreases rather than increases.
Given this information, the correct answer is:
⬜ **The frequency decreases.**
Understanding these relationships helps in comprehending fundamental concepts in physics, particularly in the study of light and electromagnetic waves.
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