8.2 Evaluate the determinants (a) a h g h g bf f с (b) HOMT 1 2 3 -2 1 3 -3 4 -2 0 -110 -2 1-2 1
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- 5. Please select the correct answer: (a) Acceleration of a free electron and its collision with the host atoms and ionize them in solid, which leads to electron avalanche breakdown. (b) The flow of a substantial current between the electrodes, which appears as a (II) Dielectric strength short between the electrodes when the voltage across a dielectric material exceeds from a critical voltage. (c) The gradual growth of microstructural voids, cracks, or pores within the dielectric due to partial discharge, which leads to electrical tree type of discharge. (d) The maximum field that can be applied to an insulating medium without causing dielectric breakdown. (I) Dielectric breakdown (III) Intrinsic Breakdown (IV) Internal Dischargesfrom 7/2 to TI from (–10) to (10) (2a) The average of f(x) = cos(3x) (2b) The average of f(x) = x² (2c) The average of f(x) = 2x sin(x) (2d) The average of f(x) = 3x from 0 to ↑ %3D from (-3) to (3)#3
- I need the answer as soon as possibleSt. John's University - My App X A ALEKS - Iffat Khan G how many valence electrons in x + i www-awn.aleks.com/alekscgi/x/lsl.exe/1o_u-lgNslkr7j8P3jH-lijkPWvZoZLqkt1FLIq7wcPWKzBYGfE9IMFjNG0dB_IllkUmxjvdZ3p44elzs8GVwNxjbe5NR20.. * O MEASUREMENT Setting up the solution to a basic quantitative problem The electric field strength between the plates of a simple air capacitor is equal to the voltage across the plates divided by the distance between them. When a voltage of 94.8 V is put across the plates of such a capacitor an electric field strength of 2.3 kV is measured. cm Write an equation that will let you calculate the distance d between the plates. Your equation should contain only symbols. Be sure you define each symbol. Your equation: d =| Definitions of your symbols: kV D = 2.3 cm = 94,8 V Explanation Check © 2021 McGraw-Hill Education. All Riahts Reserved. Terms of Use I Privacy étv II5.47 Germanium is doped with 5 × 10¹5 donor atoms per cm³ at T = 300 K. The dimen- sions of the Hall device are d = 5 x 10-³ cm, W = 2 × 10-² cm, and L = 10-¹ cm. The current is I = 250 μA, the applied voltage is V. = 100 mV, and the magnetic flux density is B₂ = 500 gauss = 5 x 10-2 tesla. Calculate: (a) the Hall voltage, (b) the Hall field, and (c) the carrier mobility.