8. What is the best fuel? Order the three samples according to the amount of heat released when 1.00 mol is combusted. a. A 1.000 g sample of the rocket fuel hydrazine (N2H4) is burned in a bomb calorimeter. The temperature rises from 24.62°C to 28.16°C. The heat capacity of the calorimeter (including the water) is 5860 J/°C. Calculate the heat of combustion of hydrazine, in kJ/mol. A: -665 kJ/mol b. A 1.000 g sample of octane (C8H18) is burned in a bomb calorimeter containing 1200 g of water at an initial temperature of 25.00°C. After the reaction, the final temperature of the water is 33.20°C. The heat capacity of the calorimeter is 837 J/°C. The specific heat of water is 4.184 J/g°C. Calculate the heat of combustion of octane in kJ/mol. A: -5500 kJ/mol c. A 0.500 g sample of TNT (C7H5N306) is burned in a bomb calorimeter containing 610 g of water at an initial temperature of 20.00°C. After the reaction, the final temperature of the water is 22.5°C. The heat capacity of the calorimeter is 420 J/°C. The specific heat of water is 4.184 J/g°C. Calculate the heat of combustion of TNT in kJ/mol. A: -3400kJ/mol

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**Title: Comparing Fuel Efficiency Using Bomb Calorimetry**

**Introduction:**

In this educational exercise, we evaluate the efficiency of three fuel samples by calculating the heat of combustion for each when 1.00 mol is burned. The fuels investigated are hydrazine (N₂H₄), octane (C₈H₁₈), and TNT (C₇H₅N₃O₆). The data gathered from bomb calorimetry experiments allows us to determine the energy each fuel releases, which is a critical factor in assessing their suitability for various applications.

**Experiment Details:**

**a. Hydrazine (N₂H₄):**

- **Sample Mass:** 1.000 g
- **Initial Temperature:** 24.62°C
- **Final Temperature:** 28.16°C
- **Calorimeter Heat Capacity:** 5860 J/°C

To determine the heat of combustion, calculate the total energy absorbed by the calorimeter using:
\[ q = \text{Calorimeter heat capacity} \times (\text{Final Temperature} - \text{Initial Temperature}) \]

**Answer:** -665 kJ/mol

---

**b. Octane (C₈H₁₈):**

- **Sample Mass:** 1.000 g
- **Water Mass:** 1200 g
- **Initial Temperature:** 25.00°C
- **Final Temperature:** 33.20°C
- **Calorimeter Heat Capacity:** 837 J/°C
- **Specific Heat of Water:** 4.184 J/g°C

Calculate the energy change in the water and calorimeter separately, then sum both to determine the overall energy release.
\[ q_{\text{water}} = \text{Water Mass} \times \text{Specific Heat of Water} \times (\text{Final Temp} - \text{Initial Temp}) \]
\[ q_{\text{calorimeter}} = \text{Calorimeter Heat Capacity} \times (\text{Final Temp} - \text{Initial Temp}) \]

**Answer:** -5500 kJ/mol

---

**c. TNT (C₇H₅N₃O₆):**

- **Sample Mass:** 0.500 g
- **Water Mass:** 610 g
- **Initial Temperature:** 20.00°C
- **Final Temperature:**
Transcribed Image Text:**Title: Comparing Fuel Efficiency Using Bomb Calorimetry** **Introduction:** In this educational exercise, we evaluate the efficiency of three fuel samples by calculating the heat of combustion for each when 1.00 mol is burned. The fuels investigated are hydrazine (N₂H₄), octane (C₈H₁₈), and TNT (C₇H₅N₃O₆). The data gathered from bomb calorimetry experiments allows us to determine the energy each fuel releases, which is a critical factor in assessing their suitability for various applications. **Experiment Details:** **a. Hydrazine (N₂H₄):** - **Sample Mass:** 1.000 g - **Initial Temperature:** 24.62°C - **Final Temperature:** 28.16°C - **Calorimeter Heat Capacity:** 5860 J/°C To determine the heat of combustion, calculate the total energy absorbed by the calorimeter using: \[ q = \text{Calorimeter heat capacity} \times (\text{Final Temperature} - \text{Initial Temperature}) \] **Answer:** -665 kJ/mol --- **b. Octane (C₈H₁₈):** - **Sample Mass:** 1.000 g - **Water Mass:** 1200 g - **Initial Temperature:** 25.00°C - **Final Temperature:** 33.20°C - **Calorimeter Heat Capacity:** 837 J/°C - **Specific Heat of Water:** 4.184 J/g°C Calculate the energy change in the water and calorimeter separately, then sum both to determine the overall energy release. \[ q_{\text{water}} = \text{Water Mass} \times \text{Specific Heat of Water} \times (\text{Final Temp} - \text{Initial Temp}) \] \[ q_{\text{calorimeter}} = \text{Calorimeter Heat Capacity} \times (\text{Final Temp} - \text{Initial Temp}) \] **Answer:** -5500 kJ/mol --- **c. TNT (C₇H₅N₃O₆):** - **Sample Mass:** 0.500 g - **Water Mass:** 610 g - **Initial Temperature:** 20.00°C - **Final Temperature:**
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