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- Use: 8086 Assembler, Code a program that will form a trees, use the word below. with different color in every word. TREES I think that | shall never see A poem lovely as a tree A tree whose hungry mouth is pressed Against the sweet earth's flowing breast A tree that looks at God all day And lifts her leafy arms to pray A tree that may in summer wear A nest of robins in her hair Upon whose bosom snow has lain Who intimately lives with rain Poems are made by fools like me But only God can Make a tree JOYCE KILMERReview the following snippet from an assembly code listing file (source assembly statements and listing file line numbers are removed purposely) and answer the questions. 00000000 B8 00000000 00000005 03 05 0000000A R 0000000B 66| 2B 15 00000008 R 00000012 41 00000013 69 15 0000000A R FFFFFED9 0000001D 8A C3 0000001F FF OD 0000000A R 00000025 661 B9 0019 1) Locate the instruction that has the smallest size object code (i.e. minimum byte-length), what is the corresponding address of the instruction? type your answer... 2) Locate the instruction that has the largest size object code (i.e. maximum byte-length). What is the byte-length of the instruction? type your answer... 3) How many of the above instructions have direct memory reference? choose your answer... 4) What is the total length (number of bytes) of the above object code snippet? type your answer... 5) How many instructions contain an opcode prefix? choose your answer...In 8051 assembly language: If one of the elements in a list in ROM is more than 8 bits in binary as shown below list: DB 9H,12H,2021H How can I separate 2021 into 2 bytes in RAM? So that one location in RAM holds 20, and the other 21. (Values in RAM should be in BCD format)
- (a) In MIPS machine language, the R format instructions need an additional field (the “funct” field) to specify the instruction type (“add”, “sub”, etc.). Why can’t this be done using just the 6-bit “op” field, which all MIPS instructions have, instead? (b) Give a sequence of MIPS assembly language instructions that adds the contents of $s0 and $s1, storing the result into $s0, if the contents of $s1 are greater than 6. Otherwise, the contents of $s0 should be incremented by 28. In either case, afterwards the contents of $s0 should be copied into $s2. (c) Suppose that the starting address of an array of words is stored in $s0. Give a MIPS assembly language instruction that loads the contents of the second word in the array into $s1. (d) Suppose that A and B are defined using “A: .word 0”, and “B: .space 100”. Give a sequence of MIPS assembly language instructions that calls a procedure “P” with its two arguments being the contents of A and the address of B, using the standard procedure…Have a question requiring an answer in assembly languageImplement the following expression in assembly language: result = (val3 + val4) - (val1 – val2) – (30*4)/55- Assume that result,val1, val2, val3 and val4 are 16-bit integer variables- You need to implement the expression the way it is provided, you cannot do any reduction on theexpression while implementing it.- Initialize val1 with 134 (hexadecimal), val2 with 139 (hexadecimal), val3 with 67(hexadecimal) and val4 with 47 (hexadecimal)- You are NOT allowed to update the values of any variables.- Use ONLY mov, add, sub, movzx, movsx, or neg instructions whenever needed.- Use the debugger to verify your answer
- Implement the following expression in assembly language: result = (val3 + val4) (vall - val2) (30*4)/55 Assume that result, vall, val2, val3 and val4 are 16-bit integer variables You need to implement the expression the way it is provided, you cannot do any reduction on the expression while implementing it. - Initialize vall with 134 (hexadecimal), va12 with 139 (hexadecimal), val3 with 67 (hexadecimal) and val4 with 47 (hexadecimal) -Mars simulator assembler programming 1. Translate these expressions in C to the corresponding expressions in MIPS assembler. Describe how to allocate variables to registers. f = gh B [4]Problem Statement Write 8086 Assembly language program to sort in descending order of the elements in a given array, which is starts from memory offset 501. The size of the series is stored at memory offset 500.
- E In the following code block(Reference:Q11), you will a set of assembly instructions with corresponding line numbers (line numbers are for informational purpose only and they are not part of the source code). 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 mov edx, 5 dec ecx jmp LABEL1 mov eax, 1 LABEL1: mul edx jmp ecx mov edx, 0678h sub edx, eax jmp DWORD PTR [edx] neg ebx add ecx, ebx mov eax, 0 For each of the conditions/scenario listed below, indicate the corresponding line number (that cause or is associated with the condition/scenario). Enter 0 (Zero) if the condition is not caused by the block of code. 1) Memory indirect jump: type your answer... type your answer... type your answer... type your answer... 2) Register indirect jump: 3) Relative short jump: type your answer... 5) Two's complement type your answer... 4) Relative near jump: 6) Unreachable codeCorrect answer gets upvote