Answered: [ 8. The wire in the figure has a… | bartleby

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Solution HW1Q7-by: write your full name here
Page 14
Page 14 of 18
b
= lnb - In a = ln
a X
a
= In(b+n)-In(a+n) In
8. The wire in the figure has a linear charge
density A. What is the electric potential
at the center of the semicircle? hint:
dx
la x + n
S dr =
dx = b - a
2R
2R
Solution HW1Q8-by: write your full name here
Page 15
dx
b + n
a + n

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8. Figure below shows a ring of outer radius R = 13.0 cm and inner radius l'inner = 0.200R. It has uniform surface charge density 0 = 6.20 pC/m². With V = 0 at infinity, find the electric potential at point P on the central axis of the ring, at distance z = 2.00R from the center of the ring. 6 dQ K √ ₁7 - Pl What is your dQ? What is your infinitesimal area element? (a) Start with the formula for the potential: V = k What are your vectors r and r'? What is the distance to point P? What is dV? Potential due to a small ring of charge on the disk? (b) Write out the integral that you need to compute to get V. What are the bounds? (c) Once you get an expression for V, solve numerically. (d) Check to see if the units of your expression makes sense for V.
Q1. What is the electric potential of a dipole on the y-axis at large distances? 1 qd 1 qd (c) V = 2nɛ, r? 1 qd 4πε r (a) V = 0 (b) V = (d) V = 2πε, r y Q2. Find the monopole term in the multi-pole expansion of the electric potential on the z- axis for a flat circular charged disk of radius R and charge density o (r,q) = krʻ cosʻ q, where k is a constant and r, q are polar coordinates with the origin at the disk's centre.
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4. Having found the voltage difference from knowing the electric field, we can also do the inverse, find the electric field if we know the voltage as a function of position. Since the inverse of integration is differentiation, we have: av Ey ây' The partial derivative OV/Ox means that to take the derivative with respect to x while treating y and z as constant. The electric potential in a region of space is given by Ex = What is the electric field in this region? av Əx' 2 5y V (x, y, z) = V. ((-)² – 57) av əz
can u help with part c asap plz
Q-2: Two concentric conducting spherical shells of radii r¡ and r, > rz. The inner shell carries a charge +Q while the outer shell carries a charge +2Q as shown. Assuming V = 0 as r → ∞, Calculate: a. The electric field vectors: E1(r r2) b. The electric potentials: V, (r r2) c. The electric potential difference between the two shells: AV
3. A thin circular ring has a radius R and charge3 Q distributed uniformly over its length. What is the electric potential at the center of the ring? Hint: this is very easy since every point on the ring is the same distance from the center. Therefore you don't need to integrate. а. 3Q, R b. What is the electric potential at a distance z along the axis of the thin ring? Comment: each point on the ring is still the same distance from point P. 3Q, R
Needs Complete typed solution with 100 % accuracy. Don't use chat gpt or ai i definitely upvote you.
4. Figure below shows a ring of outer radius R = 13.0 cm, inner radius r= 0.200R, and uniform surface charge density o = 6.20 pC/m2. With V = 0 at infinity, find the electric potential at point P on the central axis of the ring, at distance z = 2.0OR from the center of the ring. %3D R
tion A1 The electric potential V(x) for a planar charge distribution is as follows: (= (1 + 2)² =a a V(x) = where Vo is the potential at the origin and a is a distance. Derive an expression for the corre- sponding electric field Ē(x).