8. The solution of the initial-value problem x' = 5 )x, x(0) = х, is: (o) x =*" ()-*() 6) x = +()+** (;) (6) x = *" (: ) - *-* ( ) -2t -3t (b) х — — (:) = -2t (a) x - **() + ** (; ) -3t (1)- (e) None of the above.

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Q: SOLVE a'a 33. (a) (b) (a’a*)' (c) a 34. (a) (b) (2a’a*)* (c) (-3z*)'(2:")

A: Hello. Since your question has multiple parts, we will solve first question for you. If you want…

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