If f (x) = x²cos-(x² – 4), what is f'(x)? 2x3 o f'(x) = 2xcos-'(x² – 4) – V 1-(x²-4)² 2x3 o f'(x) = 2xcos-'(x² + 4) + V1-(x²-4)° 2x f'(x) = 2xcos-'(x² – 4) + 2 /1-(x²–4)' o f'(x) = 2xcos-(x² – 4) – 1-(x²+4)² |

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
If f (x) = x²cos-(x² – 4), what is f'(x) ?
2x3
o f'(x) = 2xcos-(x² – 4) –
(1-(x²–4)²
f'(x) = 2xcos-(x² + 4) +
2x3
VI-(x²-4)²
2x
f'(x) = 2xcos'(x² – 4) +
'1-(x²-4)²
o f'(x) = 2xcos-'(x² – 4) –
1-(x²+4)²
Transcribed Image Text:If f (x) = x²cos-(x² – 4), what is f'(x) ? 2x3 o f'(x) = 2xcos-(x² – 4) – (1-(x²–4)² f'(x) = 2xcos-(x² + 4) + 2x3 VI-(x²-4)² 2x f'(x) = 2xcos'(x² – 4) + '1-(x²-4)² o f'(x) = 2xcos-'(x² – 4) – 1-(x²+4)²
4
If f (x) = ,
and g(x) = f -' (x), what is g' (x) ?
x-3 '
o gʻ(x) =
2
x2
1
o gʻ(x) =
x2
o gʻ(x) = -
4
|
o g'(x) =
4
x2
Transcribed Image Text:4 If f (x) = , and g(x) = f -' (x), what is g' (x) ? x-3 ' o gʻ(x) = 2 x2 1 o gʻ(x) = x2 o gʻ(x) = - 4 | o g'(x) = 4 x2
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