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8. The long chord from the PC to PT of a compound curve is 300 meters long and the angles it makes with the longer and shorter tangents are 12o and 150 respectively. If the common tangent is parallel to the long chord. a. Find the radius of the first curve. A. 802.36 mC. 805.42 m B. 810.34 mD. 824.35 m b. Find the radius of the second curve. A. 500.23 mC. 514.55 m B. 448.97 mD. 535.32 m c. If stationing of PC is 10 + 204.30, find the stationing at PT. A. 10 + 602C. 10 + 550 B. 10 + 507D, 10 + 615

8. The long chord from the PC to PT of a compound curve is 300 meters long and the angles it makes with the longer and shorter tangents are 12o and 150 respectively. If the common tangent is parallel to the long chord. a. Find the radius of the first curve. A. 802.36 mC. 805.42 m B. 810.34 mD. 824.35 m b. Find the radius of the second curve. A. 500.23 mC. 514.55 m B. 448.97 mD. 535.32 m c. If stationing of PC is 10 + 204.30, find the stationing at PT. A. 10 + 602C. 10 + 550 B. 10 + 507D, 10 + 615

Traffic and Highway Engineering
Traffic and Highway Engineering
5th Edition
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Garber, Nicholas J.
Chapter15: Geometric Design Of Highway Facilities
Section: Chapter Questions
Problem 7P
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8. The long chord from the PC to PT of a compound curve is 300 meters long and the angles it makes with the longer and shorter tangents are 12o and 150 respectively. If the common tangent is parallel to the long chord. a. Find the radius of the first curve. A. 802.36 mC. 805.42 m B. 810.34 mD. 824.35 m b. Find the radius of the second curve. A. 500.23 mC. 514.55 m B. 448.97 mD. 535.32 m c. If stationing of PC is 10 + 204.30, find the stationing at PT. A. 10 + 602C. 10 + 550 B. 10 + 507D. 10 + 615
Transcribed Image Text:8. The long chord from the PC to PT of a compound curve is 300 meters long and the angles it makes with the longer and shorter tangents are 12o and 150 respectively. If the common tangent is parallel to the long chord. a. Find the radius of the first curve. A. 802.36 mC. 805.42 m B. 810.34 mD. 824.35 m b. Find the radius of the second curve. A. 500.23 mC. 514.55 m B. 448.97 mD. 535.32 m c. If stationing of PC is 10 + 204.30, find the stationing at PT. A. 10 + 602C. 10 + 550 B. 10 + 507D. 10 + 615
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