8. The following data were collected for several compounds of nitrogen and oxygen: Mass of Oxygen That Reacts with 1.000 g of Nitrogen Compound

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Why is the answer not A?

**Title: Analyzing Compounds of Nitrogen and Oxygen**

**Objective:**
In this exercise, we examine the mass of oxygen that reacts with 1.000 g of nitrogen to determine possible chemical formulas for specific compounds.

**Data Table:**
Below is the data collected for various compounds of nitrogen and oxygen:

| **Compound** | **Mass of Oxygen That Reacts with 1.000 g of Nitrogen** |
|--------------|-------------------------------------------------------|
| W            | 0.5711 g                                             |
| X            | 1.142 g                                              |
| Y            | 2.284 g                                              |
| Z            | 2.855 g                                              |

**Question:**
If compound X has an equal number of oxygen and nitrogen atoms, what is the most likely formula for compound Y?

**Options:**
(A) NO  
(B) NO₂  
(C) N₂O  
(D) N₂O₅

**Explanation:**
- Compound X has a mass of 1.142 g of oxygen reacting with 1.000 g of nitrogen.
- Given that compound X has an equal number of oxygen and nitrogen atoms, the simplest formula that fits is NO (Nitric Oxide).

To find the formula for compound Y:
- Observing the data: The mass of oxygen for compound Y is exactly double that for compound X.
- This suggests that compound Y has twice as many oxygen atoms as compound X.

Therefore, if X (NO) has one oxygen atom, then Y likely has two oxygen atoms, leading to the formula NO₂ for compound Y.

**Final Answer:**
(B) NO₂

**Conclusion:**
By analyzing the given mass relationships and applying stoichiometric principles, we deduce that if compound X is represented by the formula NO, then compound Y, having twice the mass of oxygen per nitrogen atom, is NO₂.
Transcribed Image Text:**Title: Analyzing Compounds of Nitrogen and Oxygen** **Objective:** In this exercise, we examine the mass of oxygen that reacts with 1.000 g of nitrogen to determine possible chemical formulas for specific compounds. **Data Table:** Below is the data collected for various compounds of nitrogen and oxygen: | **Compound** | **Mass of Oxygen That Reacts with 1.000 g of Nitrogen** | |--------------|-------------------------------------------------------| | W | 0.5711 g | | X | 1.142 g | | Y | 2.284 g | | Z | 2.855 g | **Question:** If compound X has an equal number of oxygen and nitrogen atoms, what is the most likely formula for compound Y? **Options:** (A) NO (B) NO₂ (C) N₂O (D) N₂O₅ **Explanation:** - Compound X has a mass of 1.142 g of oxygen reacting with 1.000 g of nitrogen. - Given that compound X has an equal number of oxygen and nitrogen atoms, the simplest formula that fits is NO (Nitric Oxide). To find the formula for compound Y: - Observing the data: The mass of oxygen for compound Y is exactly double that for compound X. - This suggests that compound Y has twice as many oxygen atoms as compound X. Therefore, if X (NO) has one oxygen atom, then Y likely has two oxygen atoms, leading to the formula NO₂ for compound Y. **Final Answer:** (B) NO₂ **Conclusion:** By analyzing the given mass relationships and applying stoichiometric principles, we deduce that if compound X is represented by the formula NO, then compound Y, having twice the mass of oxygen per nitrogen atom, is NO₂.
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