8. The following data were collected for several compounds of nitrogen and oxygen: Mass of Oxygen That Reacts with 1.000 g of Nitrogen Compound
8. The following data were collected for several compounds of nitrogen and oxygen: Mass of Oxygen That Reacts with 1.000 g of Nitrogen Compound
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Why is the answer not A?
![**Title: Analyzing Compounds of Nitrogen and Oxygen**
**Objective:**
In this exercise, we examine the mass of oxygen that reacts with 1.000 g of nitrogen to determine possible chemical formulas for specific compounds.
**Data Table:**
Below is the data collected for various compounds of nitrogen and oxygen:
| **Compound** | **Mass of Oxygen That Reacts with 1.000 g of Nitrogen** |
|--------------|-------------------------------------------------------|
| W | 0.5711 g |
| X | 1.142 g |
| Y | 2.284 g |
| Z | 2.855 g |
**Question:**
If compound X has an equal number of oxygen and nitrogen atoms, what is the most likely formula for compound Y?
**Options:**
(A) NO
(B) NO₂
(C) N₂O
(D) N₂O₅
**Explanation:**
- Compound X has a mass of 1.142 g of oxygen reacting with 1.000 g of nitrogen.
- Given that compound X has an equal number of oxygen and nitrogen atoms, the simplest formula that fits is NO (Nitric Oxide).
To find the formula for compound Y:
- Observing the data: The mass of oxygen for compound Y is exactly double that for compound X.
- This suggests that compound Y has twice as many oxygen atoms as compound X.
Therefore, if X (NO) has one oxygen atom, then Y likely has two oxygen atoms, leading to the formula NO₂ for compound Y.
**Final Answer:**
(B) NO₂
**Conclusion:**
By analyzing the given mass relationships and applying stoichiometric principles, we deduce that if compound X is represented by the formula NO, then compound Y, having twice the mass of oxygen per nitrogen atom, is NO₂.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F40e25f29-5021-499e-9c49-7da7bd92383c%2Fd3afdafb-6834-4b96-93cc-55942c6bcc19%2Fkbejjz.png&w=3840&q=75)
Transcribed Image Text:**Title: Analyzing Compounds of Nitrogen and Oxygen**
**Objective:**
In this exercise, we examine the mass of oxygen that reacts with 1.000 g of nitrogen to determine possible chemical formulas for specific compounds.
**Data Table:**
Below is the data collected for various compounds of nitrogen and oxygen:
| **Compound** | **Mass of Oxygen That Reacts with 1.000 g of Nitrogen** |
|--------------|-------------------------------------------------------|
| W | 0.5711 g |
| X | 1.142 g |
| Y | 2.284 g |
| Z | 2.855 g |
**Question:**
If compound X has an equal number of oxygen and nitrogen atoms, what is the most likely formula for compound Y?
**Options:**
(A) NO
(B) NO₂
(C) N₂O
(D) N₂O₅
**Explanation:**
- Compound X has a mass of 1.142 g of oxygen reacting with 1.000 g of nitrogen.
- Given that compound X has an equal number of oxygen and nitrogen atoms, the simplest formula that fits is NO (Nitric Oxide).
To find the formula for compound Y:
- Observing the data: The mass of oxygen for compound Y is exactly double that for compound X.
- This suggests that compound Y has twice as many oxygen atoms as compound X.
Therefore, if X (NO) has one oxygen atom, then Y likely has two oxygen atoms, leading to the formula NO₂ for compound Y.
**Final Answer:**
(B) NO₂
**Conclusion:**
By analyzing the given mass relationships and applying stoichiometric principles, we deduce that if compound X is represented by the formula NO, then compound Y, having twice the mass of oxygen per nitrogen atom, is NO₂.
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