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- 4. The manager of the Publix in Clemson, SC believes that in his store proportion of shoppers that feel that supermarket brands are the same as national brands (Psc) is different than the proportion that feel that way in the Raleys chain of stores (PR). As a result, he asked a random sample of 100 shoppers whether they believed that supermarket brand ketchup was as good as the national brand ketchup. Hypotheses Ho: H: Direction of the extreme: 5. John Calipari, head basketball coach for the 2012 national champion University of Kentucky Wildcats, is the highest paid coach in college basketball with an annual salary of $5.4 million (as of March 29, 2012). It is thought that the mean of basketball coaches' salaries across colleges and universities (uc) are fairly varied but the NCAA suggests that the mean of coaches' salaries in the NCAA (UN) is higher than the mean across colleges and universities. Hypotheses Ho: Direction of the extreme:3a. Formulate hypotheses so that, if the null hypothesis is rejected, we can conclude that salaries for staff nurses in Tampa are lower than for those in Dallas. Use α=0.05. Let Tampa be population 1. Tampa Dallas xbar 51900 53200 s 6000 6000 n 60 60 What is the value of the test statistic?1. The null hypothesis if you are trying to find out if you have enough evidence to conclude that the population means is different than 55 would be Ha: µ ≠ 55 True False 2. A p-value of 0.017 provides more evidence against the null hypothesis than a p-value of 0.005. True False
- A psychologist wants to know whether viewing more violent TV shows affects aggressive behavior. 12 children were chosen at random for an experiment and randomly allocated to one of two conditions. In condition 1, six kids were given an aggressive behavior test. The more aggressive the conduct, the higher the score. In condition 2, six children were given the identical test after watching two hours of tv shows. The following results were obtained. Condition 1 5 14 6 8 7 6 Condition 2 12 14 14 8 15 9 Assume the obtained value of the appropriate statistic is t obt = -2.431, using α = 0.05, 2 tail, and t crit = +2.228 and -2.228, what do you conclude? a. retain null hypothesis, suggesting that violent TV show does not affect aggression. b. reject null hypothesis, suggesting that violent TV show affects aggression.For a population with a mean of m= 80, any score greater than 80 will have a positive z-score. Question 24 options: True False(b) The state of Wisconsin would like to understand the fraction of its adult residents that consumed alcohol in the last year, specifically if the rate is different from the national rate of 70%. To help them answer this question, they conduct a random sample of 852 residents and ask them about their alcohol consumption. In symbols, the hypotheses are: Ho: p = 596 Ha: p > 596 Но: р %3 0.70 На: р > 0.7 Ho: p = 596 На: # 596 Ho: p = 0.70 Ha: p z 0.70
- You take 115 random samples from a population of trees for which the mean height in feet is μ=72μ=72 (but you do not know this), and use each set of data to do a hypothesis test at a 5% level of significance to determine if the population mean is not 72. So the hypotheses are:Ho:μ=72Ho:μ=72Ha:μ≠72Ha:μ≠72In how many of the 115 hypothesis tests would you expect to reject Ho and conclude that the population mean is not 72? Do not round your answer.A psychologist wants to know whether viewing more violent TV shows affects aggressive behavior. 12 children were chosen at random for an experiment and randomly allocated to one of two conditions. In condition 1, six kids were given an aggressive behavior test. The more aggressive the conduct, the higher the score. In condition 2, six children were given the identical test after watching two hours of tv shows. The following results were obtained. Condition 1 5 14 6 8 7 6 Condition 2 12 14 14 8 15 9 Q1, The alternative (H1) hypothesis and null (H0) hypothesis are (2-tail) _________. a. H1: violent TV show does not affects aggressive behavior H0: violent TV show affects aggressive behavior b. H1: violent TV show affects aggressive behavior H0: violent TV show does not affect aggressive behavior. It is estimated that about 5% of the professors at Metro State University use illegaldrugs. Suppose random drug testing is instituted by state law. The drug test used hascertain error rates: 6% of the drug users receive a (false) negative test result, and 4% ofthe non-drug users receive a (false) positive test result. If they test me next week and thetest result comes back positive, how likely is it that I actually do use illegal drugs?
- Refer to the following scenario. A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these social outreach programs should be located based on the percentage of residents living below the poverty line in each region of the city. He takes a simple random sample of 120 people living in Gastown and finds that 21 have an annual income that is below the poverty line. For each of the following statements, specify whether the statement is a correct interpretation of the 95% confidence interval for the true proportion of Gastown residents living below the poverty line. A. 17.50% (21/120) of Gastown residents are living below the poverty line. ? B. There is a 95% probability that the true proportion of Gastown residents who are living below the poverty line equals 21/120. C. If another random sample of 120 Gastown residents is drawn, there is a 95% probability that the sample proportion of Gastown residents who are living below…Refer to the following scenario. A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these social outreach programs should be located based on the percentage of residents living below the poverty line in each region of the city. He takes a simple random sample of 123 people living in Gastown and finds that 24 have an annual income that is below the poverty line. For each of the following statements, specify whether the statement is a correct interpretation of the 95% confidence interval for the true proportion of Gastown residents living below the poverty line. A. 19.51% (24/123) of Gastown residents are living below the poverty line. ? + B. There is a 95% probability that the true proportion of Gastown residents who are living below the poverty line equals 24/123. ? + C. If another random sample of 123 Gastown residents is drawn, there is a 95% probability that the sample proportion of Gastown residents who are living…▾ Part 1 of 4 A pharmaceutical company claims their new diabetes medication results in less variance in a patient's glucose level than if the patient were on no medication at all. An endocrinologist wishes to test this claim. She divides participants randomly into two groups. Group A consists of 20 diabetics who received the medication; group B consists of 26 diabetics who received a placebo. After two weeks, the blood sugar level of each patient in each group was measured with the following results (in mg/dL): Group A: 77.8, 229.4, 199.9, 110.1, 180.2, 116.1, 139.7, 171.1, 37.4, 158.1, 88.4, 195.5, 246.1, 142.4, 178.1, 105.5, 179.6, 146.1, 78.8, 123.7 Group B: 124.5, 130.1, 136, 162.8, 113.4, 72.8, 142.6, 50.3, 179.8, 197, 230, 194.3, 171, 109.3, 114.4, 107.5, 114.7, 195.3, 127.7, 126.4, 85.6, 166.7, 182.3, 113.5, 216.7, 162.8 Perform a hypothesis test using a 6% level of significance to test the pharmaceutical company's claim. Step 1: State the null and alternative hypotheses. Ho:…
