8. PROBLEM SOLVING: Solve the following problems and answer the questions that follow 1. Suppose that random samples of size 4 are taken from this population 8, 12, 16, 20 24 and 28. Answer the questions that follow a. Using nC formula, how many possible samples of size 4 can be drawn from the population? Solution 6C4= b The possible samples are given below find its corresponding mean POSSIBLE SAMPLES SAMPLE MEAN 8,12,16,20 8,12,16.24 8,12,16.28 X 8,12,20,24 71 8,12,20,28 8,12,24,28 Example: 8,16,20,24 8,16,20 28 8,16,24,28 8,20,24,28 12.16,20,24 Sample mean is 14 12.16 20.28 12,16,24,28 12,20,24,28 16,20,24.28 cComplete the sampling distribution of the sample means SAMPLE MEAN FREQUENCY PROBABILITY P(X) X 8+12+16+20 =14

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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8. PROBLEM SOLVING: Solve the following problems and answer the questions that follow
1. Suppose that random samples of size 4 are taken from this population 8, 12, 16, 20. 24 and 28 Answer the questions
that follow
a. Using nC formula, how many possible samples of size 4 can be drawn from the population?
Solution 6C4=
b The possible samples are given below find its corresponding mean
POSSIBLE SAMPLES
SAMPLE MEAN
8,12,16,20
8,12,16.24
8,12,16.28
X =
71
8,12,20,24
8,12,20,28
8,12,24,28
Example:
8,16,20,24
8,16,20 28
Ex 56
==
=
8,16,24,28
71
8,20,24,28
12 16 20 24
12.16,20 28
Sample mean is 14
12,16,24,28
12,20,24,28
16.20,24.28
o Complete the sampling distribution of the sample means
SAMPLE MEAN
X
FREQUENCY
1
PROBABILITY
P(X)
8+12+16+20
4
=14
Transcribed Image Text:8. PROBLEM SOLVING: Solve the following problems and answer the questions that follow 1. Suppose that random samples of size 4 are taken from this population 8, 12, 16, 20. 24 and 28 Answer the questions that follow a. Using nC formula, how many possible samples of size 4 can be drawn from the population? Solution 6C4= b The possible samples are given below find its corresponding mean POSSIBLE SAMPLES SAMPLE MEAN 8,12,16,20 8,12,16.24 8,12,16.28 X = 71 8,12,20,24 8,12,20,28 8,12,24,28 Example: 8,16,20,24 8,16,20 28 Ex 56 == = 8,16,24,28 71 8,20,24,28 12 16 20 24 12.16,20 28 Sample mean is 14 12,16,24,28 12,20,24,28 16.20,24.28 o Complete the sampling distribution of the sample means SAMPLE MEAN X FREQUENCY 1 PROBABILITY P(X) 8+12+16+20 4 =14
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