8. Let AL, BM, and CN be three concurrent Cevians of AABC. Use Menelaus' theorem to prove that AN BL CM x = 1. (Hint: Apply Menelaus' theorem to the two triangles associated to transversals BFM [points NB LC MA and M are collinear] and AFL [points A, F, and L are collinear]). AH + Cl be thi
8. Let AL, BM, and CN be three concurrent Cevians of AABC. Use Menelaus' theorem to prove that AN BL CM x = 1. (Hint: Apply Menelaus' theorem to the two triangles associated to transversals BFM [points NB LC MA and M are collinear] and AFL [points A, F, and L are collinear]). AH + Cl be thi
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I need help I can’t figure out the last part
![8. Let AL, BM, and CN be three concurrent Cevians of AABC. Use Menelaus' theorem to prove that
AN BLCM
X
x
A
B
-= 1. (Hint: Apply Menelaus' theorem to the two triangles associated to transversals BFM [points
NB LC MA
and M are collinear] and AFL [points A, F, and L are collinear]).:
M
F
N
B
Let, AL, BM,+ EAS! be the
concurrent devians, we
to prove that AN. BL
LC
Applying Mentlaus theor
Мерували
A ABM
ABF
we
obtain
"
ewrite
as
AN
NB FM MA = -1₁ we
MC = -10
BF
pplying Menalaus, theren 13 FM"
FM CA-1
o transversal AFT + AALB we obtain AE.LG.CM
ve can rewrite as AE LC, BM = =+
•bf.m FL LB
hus,
NA
AN
NB FM MA = AF, LB.CM
FL
ма
FL](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27b38c32-736b-4354-8263-82b5dd937d13%2F8213b546-cbe9-4488-bd4b-94c44840da5c%2Fqr7l0fm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:8. Let AL, BM, and CN be three concurrent Cevians of AABC. Use Menelaus' theorem to prove that
AN BLCM
X
x
A
B
-= 1. (Hint: Apply Menelaus' theorem to the two triangles associated to transversals BFM [points
NB LC MA
and M are collinear] and AFL [points A, F, and L are collinear]).:
M
F
N
B
Let, AL, BM,+ EAS! be the
concurrent devians, we
to prove that AN. BL
LC
Applying Mentlaus theor
Мерували
A ABM
ABF
we
obtain
"
ewrite
as
AN
NB FM MA = -1₁ we
MC = -10
BF
pplying Menalaus, theren 13 FM"
FM CA-1
o transversal AFT + AALB we obtain AE.LG.CM
ve can rewrite as AE LC, BM = =+
•bf.m FL LB
hus,
NA
AN
NB FM MA = AF, LB.CM
FL
ма
FL
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