8. Glycolysis involves ten biochemical reactions. The first two reactions of the glycolysis cycle are (1) C,H12O6(aq) + ATP(aq) 2 G6P(aq)+ ADP(aq) AH1 = -19.74 kJ.mol-' and K1 = 4.6 × 10³ at 37°C (2) G6P(aq) 2 F6P(aq) AH2 = -2.84 kJ.mol- and K2 = 2.8 × 10-' at 37°C a. Calculate the equilibrium constant for the reaction producing F6P and ADP from C6H12O6 and ATP. b. Calculate the equilibrium concentration of F6P(aq) generated by glycolysis in a normal body at 37°C, starting with 1.20 × 10-° mol.L' glucose, 1.00 x 10ª mol.L·' ATP, and 1.00 x 10-2 mol.L·' ADP. c. During a fever, the body temperature will increase. Will the concentration of F6P increase or decrease?

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8. Glycolysis involves ten biochemical reactions. The first two reactions of the glycolysis cycle are :
(1) C6H12O6(aq) + ATP(aq) 2 G6P(aq)+ ADP(aq) AH1 =-19.74 kJ.mol- and K1 = 4.6 × 103 at 37°C
%3D
(2)
G6P(aq) 2 F6P(aq)
AH2 = -2.84 kJ.mol- and K2 = 2.8 × 10- at 37°C
%3D
%3D
a.
Calculate the equilibrium constant for the reaction producing F6P and ADP from C6H12O6
and ATP.
b. Calculate the equilibrium concentration of F6P(aq) generated by glycolysis in a normal
body at 37°C, starting with 1.20 × 10-° mol.L glucose, 1.00 × 104 mol.L ATP, and 1.00
x 10-2 mol.L- ADP.
c. During a fever, the body temperature will increase. Will the concentration of F6P increase
or decrease?
Transcribed Image Text:8. Glycolysis involves ten biochemical reactions. The first two reactions of the glycolysis cycle are : (1) C6H12O6(aq) + ATP(aq) 2 G6P(aq)+ ADP(aq) AH1 =-19.74 kJ.mol- and K1 = 4.6 × 103 at 37°C %3D (2) G6P(aq) 2 F6P(aq) AH2 = -2.84 kJ.mol- and K2 = 2.8 × 10- at 37°C %3D %3D a. Calculate the equilibrium constant for the reaction producing F6P and ADP from C6H12O6 and ATP. b. Calculate the equilibrium concentration of F6P(aq) generated by glycolysis in a normal body at 37°C, starting with 1.20 × 10-° mol.L glucose, 1.00 × 104 mol.L ATP, and 1.00 x 10-2 mol.L- ADP. c. During a fever, the body temperature will increase. Will the concentration of F6P increase or decrease?
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