**Alkyne Reactions with HBr and Br₂: Major Products****8. Give the major product for each reaction.**1. **Reaction with HBr (1 equivalent):** - **Starting Compound:** An alkyne. - **Reagent:** HBr (1 equivalent). - **Explanation:** The alkyne reacts with one equivalent of HBr, resulting in the formation of a bromoalkene as the major product.2. **Reaction with HBr (excess), symmetrical alkyne:** - **Starting Compound:** A symmetrical alkyne. - **Reagent:** HBr (excess). - **Explanation:** The symmetrical alkyne undergoes a more extensive reaction with an excess of HBr, leading to the formation of a dibromoalkane as the major product.3. **Reaction with HBr (excess):** - **Starting Compound:** An unsymmetrical alkyne. - **Reagent:** HBr (excess). - **Explanation:** In this case, two products are formed due to the unsymmetrical nature of the alkyne. The reaction results in the addition of two bromine atoms across the triple bond.4. **Reaction with Br₂ (1 equivalent):** - **Starting Compound:** An alkyne. - **Reagent:** Br₂ (1 equivalent). - **Explanation:** The alkyne reacts with one equivalent of Br₂, resulting in the formation of a dibromoalkene as the major product.5. **Reaction with HBr, in the presence of ROOR:** - **Starting Compound:** An alkyne. - **Reagent:** HBr in the presence of ROOR (a radical initiator). - **Explanation:** The presence of ROOR leads to a radical addition pathway, resulting in two products. The exact nature of the major products depends on the regioselectivity controlled by radical mechanism and the structure of the starting alkyne.These reactions and their products are fundamental in organic chemistry, particularly in the study of addition reactions of alkynes. Understanding the product formations from these reactions is crucial for further exploring the synthesis and reactivity of organic compounds.

HBr add in cis manner to alkyne forms alkene if HBr present in 1 equivalent.

Answered: 8. Give the major product for each. HBr…

8. Give the major product for each. HBr HBr (1 eq) excess HBr HBr excess excess symmetrical alkyne (2 products) Br2 HBr (1 еq) ROOR (2 products)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Reactions of Ethers

Ethers (R-O-R’) are compounds formed by replacing hydrogen atoms of an alcohol (R-OH compound) or a phenol (C6H5OH) by an aryl/ acyl group (functional group after removing single hydrogen from an aromatic ring). In this section, reaction, preparation and behavior of ethers are discussed in the context of organic chemistry.

Epoxides

Epoxides are a special class of cyclic ethers which are an important functional group in organic chemistry and generate reactive centers due to their unusual high reactivity. Due to their high reactivity, epoxides are considered to be toxic and mutagenic.

Williamson Ether Synthesis

An organic reaction in which an organohalide and a deprotonated alcohol forms ether is known as Williamson ether synthesis. Alexander Williamson developed the Williamson ether synthesis in 1850. The formation of ether in this synthesis is an SN2 reaction.

Question

**Alkyne Reactions with HBr and Br₂: Major Products**

**8. Give the major product for each reaction.**

1. **Reaction with HBr (1 equivalent):**
- **Starting Compound:** An alkyne.
- **Reagent:** HBr (1 equivalent).
- **Explanation:** The alkyne reacts with one equivalent of HBr, resulting in the formation of a bromoalkene as the major product.

2. **Reaction with HBr (excess), symmetrical alkyne:**
- **Starting Compound:** A symmetrical alkyne.
- **Reagent:** HBr (excess).
- **Explanation:** The symmetrical alkyne undergoes a more extensive reaction with an excess of HBr, leading to the formation of a dibromoalkane as the major product.

3. **Reaction with HBr (excess):**
- **Starting Compound:** An unsymmetrical alkyne.
- **Reagent:** HBr (excess).
- **Explanation:** In this case, two products are formed due to the unsymmetrical nature of the alkyne. The reaction results in the addition of two bromine atoms across the triple bond.

4. **Reaction with Br₂ (1 equivalent):**
- **Starting Compound:** An alkyne.
- **Reagent:** Br₂ (1 equivalent).
- **Explanation:** The alkyne reacts with one equivalent of Br₂, resulting in the formation of a dibromoalkene as the major product.

5. **Reaction with HBr, in the presence of ROOR:**
- **Starting Compound:** An alkyne.
- **Reagent:** HBr in the presence of ROOR (a radical initiator).
- **Explanation:** The presence of ROOR leads to a radical addition pathway, resulting in two products. The exact nature of the major products depends on the regioselectivity controlled by radical mechanism and the structure of the starting alkyne.

These reactions and their products are fundamental in organic chemistry, particularly in the study of addition reactions of alkynes. Understanding the product formations from these reactions is crucial for further exploring the synthesis and reactivity of organic compounds.

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