8. First calculate the virtual conditions and resultant conditions for the pin and hole in the figure below (figure on the following page). Then calculate the maximum and minimum distances for dimensions X and Y. a. The Virtual Condition of the PIN: VCp = = MMC + Geo. Tol. = b. The Virtual Condition of the HOLE: VCh = MMC-Geo. Tol. = c. Resultant Condition of the PIN: RCP= LMC-Geo. Tol. - Bonus = d. Resultant Condition of the HOLE: RCh = LMC+ Geo. Tol. + Bonus = e. The maximum distance for dimension X: XMax = Dist. - RCp/2-VCh/2= f. The minimum distance for dimension X: XMin = Dist. VCp /2 - RCh /2 = g. The maximum distance for dimension Y: YMax-Dist. @ MMC-Basic Dimension - VCh/2 = h. The minimum distance for dimension Y:

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.7.10P: Solve the preceding problem for the following data: x=190106,y=230106,xy=160106,and=45.
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1.000
C
1.500
Ø.998-1.00
+0.004MABC
X
3.000
6.00
01.000-1.006
+0.004M ABC
Y
B
A
Unless Otherwise Specified:
.XX = = .01
ANGLES = ± 1°
Transcribed Image Text:1.000 C 1.500 Ø.998-1.00 +0.004MABC X 3.000 6.00 01.000-1.006 +0.004M ABC Y B A Unless Otherwise Specified: .XX = = .01 ANGLES = ± 1°
8. First calculate the virtual conditions and resultant conditions for the pin and hole in the figure below (figure on the following page). Then calculate the maximum and minimum distances for dimensions X
and Y.
a. The Virtual Condition of the PIN:
VCp = MMC + Geo. Tol. =
b. The Virtual Condition of the HOLE:
VCh = MMC-Geo. Tol. =
c. Resultant Condition of the PIN:
RCP = LMC-Geo. Tol. - Bonus =_
d. Resultant Condition of the HOLE:
RCh = LMC + Geo. Tol. + Bonus =
e. The maximum distance for dimension X:
XMax = Dist. - RCp/2 - VCh/2 =
f. The minimum distance for dimension X:
XMin = Dist. VCp /2 - RCh /2 =
g. The maximum distance for dimension Y:
YMax =Dist. @ MMC - Basic Dimension - VCh/2 =
h. The minimum distance for dimension Y:
YMin = Dist. @ LMC - Basic Dimension - RCh/2 =
Transcribed Image Text:8. First calculate the virtual conditions and resultant conditions for the pin and hole in the figure below (figure on the following page). Then calculate the maximum and minimum distances for dimensions X and Y. a. The Virtual Condition of the PIN: VCp = MMC + Geo. Tol. = b. The Virtual Condition of the HOLE: VCh = MMC-Geo. Tol. = c. Resultant Condition of the PIN: RCP = LMC-Geo. Tol. - Bonus =_ d. Resultant Condition of the HOLE: RCh = LMC + Geo. Tol. + Bonus = e. The maximum distance for dimension X: XMax = Dist. - RCp/2 - VCh/2 = f. The minimum distance for dimension X: XMin = Dist. VCp /2 - RCh /2 = g. The maximum distance for dimension Y: YMax =Dist. @ MMC - Basic Dimension - VCh/2 = h. The minimum distance for dimension Y: YMin = Dist. @ LMC - Basic Dimension - RCh/2 =
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