### Problem Statement:8. **Design rectangular sections for the beams, loads, and ρ values shown. Beam weights are not included in the loads shown. Show sketches of cross sections, including bar sizes, arrangement, and spacing. Assume concrete weighs 150 lb/ft³, f_y = 60,000 psi, and f_c = 4000 psi, unless given otherwise.**#### Diagram (a):- **Load Information:** - Point Load (P_L) = 30 k - Uniformly Distributed Load (w_D) = 3 k/ft- **Beam Lengths:** - Segment Length = 12 ft - Total Span Length = 24 ft- **Reinforcement Ratio Formula:** - Use ρ = \(\dfrac{0.18 f'_{c}}{f_{y}}\)Diagram (a) shows a simply supported beam with a point load P_L in the middle of the span (total span 24 ft, divided equally into two 12 ft segments) and a uniformly distributed load (w_D). The cross-sectional sketch should include the arrangement of bars according to the reinforcement ratio provided.#### Diagram (b):- **Load Information:** - Point Load (P_L) = 36 k - Uniformly Distributed Load (w_D) = 2 k/ft- **Beam Lengths:** - Section Length = 10 ft - Section Length = 20 ft - Total Span Length = 30 ft- **Reinforcement Ratio Formula:** - Use ρ = \(\dfrac{1}{2} ρ_b\)Diagram (b) shows a simply supported beam with a point load P_L placed 10 ft from the left support (total span 30 ft, segmented into 10 ft and 20 ft sections) and a uniformly distributed load (w_D). The cross-sectional sketch should incorporate the arrangement of bars following the given reinforcement ratio.### Key Parameters and Assumptions:- **Material Weight:** - Concrete Weight = 150 lb/ft³- **Material Strengths:** - Steel Yield Strength (f_y) = 60,000 psi - Concrete Compressive Strength (f_c) = 4000 psiFor each part, ensure detailed sketches of cross-sections include the size and spacing of reinforcement bars,

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8. Design rectangular sections for the beams, loads, and p values shown. Beam weights are not included in the loads shown. Show sketches of cross sections, including bar sizes, arrangement, and spacing. Assume concrete weighs 150 lb/ft3, fy = 60,000 psi, and f c = 4000 psi, unless given otherwise. a) 12 ft P₁ = 30 k 24 ft Use p= WD = 3 k/ft 12 ft 0.18 f'e fy PL = 36 k 10 ft-> 30 ft Use P= 20 ft == Pb WD = 2 k/ft

8. Design rectangular sections for the beams, loads, and p values shown. Beam weights are not included in the loads shown. Show sketches of cross sections, including bar sizes, arrangement, and spacing. Assume concrete weighs 150 lb/ft3, fy = 60,000 psi, and f c = 4000 psi, unless given otherwise. a) 12 ft P₁ = 30 k 24 ft Use p= WD = 3 k/ft 12 ft 0.18 f'e fy PL = 36 k 10 ft-> 30 ft Use P= 20 ft == Pb WD = 2 k/ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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