Answered: 8. Continue example 7. Declare a…

8. Continue example 7. Declare a variable called staffl of type SEmployee. Assign by list, 3001 to elD, "Analyst 1" to eTitle, "Boris Elstin" to eName, and 55000.00 to eSalary.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

100%

Need help with example 8, code is attached. Please and thank you

9:51
* l 34%I
Finclude <iostream>
using namespace std;
struct sEmployee
{
int eId;
string eName;
string eTitle;
double eSalary;
};
void print(sEmployee s){
cout<<"The employee Id is:"<<s
.eId<<endl;
cout<<"The employee name is:"
<<s.eName<<endl;
cout<<"The employee title is:"
<<s.eTitle<<endl;
cout<<"The employee Salary is:"
<<s.eSalary<<endl;
}
int main(void) {
struct sEmployee admn;
admn.eId = 2001;
admn.eName = "Hari";
admn.eTitle="Manager";
admn.eSalary=120000;
print(admn);
return 0;
Run

6:48 M
3 all 97%|
M10- Structs - Read-only
Example 7, 8, 9
7. Continue example 5. Write a print function for sEmployee struct
that will print as shown in example 5. Call this function instead of
the print statement(s) in example 5.
8. Continue example 7. Declare a variable called staffl of type
sEmployee. Assign by list, 3001 to elD, “Analyst 1" to eTitle,
"Boris Elstin" to eName, and 55000.00 to eSalary.
9. Continue example 8. Declare a variable called staff2 of type
sEmployee. Assign by individual members, 3002 to elID, "Analyst
2" to eTitle, "Cameron Diaz" to eName, and 58000.00 to eSalary.
Notes
Comments
Eupla 6 function to print struct
Eumpla 7,8.9
Anay of struct- Eumple
. s.ca omild
a tng
dreten Atets i Att l
i
+
de igte
Tuidak T d
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