8. Consider a fuzzy set old as defined belowold={(20,0), (30,0.2),(40,0.4),be (A){(40,0.3))(B){50,60,70,80}(50,0.6),(60,0.8),(70,1),(80,1)). Then the alpha-cut for alpha=0.4 for the set old will(C){(20,0.1), (30,0.2)}(D){(20,0), (30,0), (40,1),(50,1),(60,1),(70,1),(80,1))

Answered: 8. Consider a fuzzy set old as defined…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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5 Calculate XkYk for the n = 5 data points (×₁,Y₁ ) = (2,4), (×2,Y₂) = (3,5), (×3,Y3) = (4,8), (×4,Y4) = (5,10), and k=1 (X5,5) = (6,14). 5 Σ xxYk = [ k=1 (Simplify your answer.)
X = factorial(3) def factorial(n): if n == 1:return 1else:return n* factorial (n-1) def factorial(n):if n== 1: return 1else: 2return n * factorial(n-1) def factorial(n):if n==1: return 1 else:return n* factorial (n-1) Provide a relationship with the domain subset of the integers that is proven using mathematical induction
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Students at certain university have to pass of one these three courses (MAT102, STA105, and PHY110). The pass rates for the courses MAT 102, STA105, and PHY110 are 0.54, 0.79, and 0.86, respectively. Suppose that 30 candidates take the MAT102 course, 25 take the STA105 course and 20 take the PHY110 coruse. A student takes one of these courses and passes. What are the probabilities that she took MAT102, STA105 or PHY110? Hint: Denote by Q the event a student to pass their course. Now denote by R1, R2 and R3 the events to take courses MAT102, STA105, and PHY110. The pass reates then represent the conditional probabilites: P(Q| R1), P(Q| R2) and P(Q| R3). The number of students taking the courses can be used to estimate the probabilities for R1, R2 and R3. For example, since there are total of 30 + 25 + 20 = 75 students that take the courses, for R1 we have: P(R1) = 30/75 = 2/5 What you are asked is: given that a student passes (event Q) estimate the probabilities that she took MAT102…

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8. Consider a fuzzy set old as defined below old={(20,0),(30,0.2),(40,0.4),(50,0.6),(60,0.8),(70,1),(80,1)). Then the alpha-cut for alpha=0.4 for the set old will be (A){(40,0.3)} (B){50,60,70,80} (C){(20,0.1),(30,0.2)) (D){(20,0),(30,0),(40,1),(50,1),(60,1),(70,1),(80,1))