8. Block Mı is on top of block M2 which is on top of a horizontal, frictionless surface. A horizontal force, F, is applied to M1. The coefficient of static friction is µs and the coefficient of kinetic friction is µk. Find, a) the maximum force that can be applied to M1, such that the position of Mi relative to M2 will not change. (Mi will not slip on top of M2). Then, if the force acting on Mi is doubled, or F' = 2F, find the acceleration of each mass. M, friction M2 no friction

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Chapter6: Applications Of Newton's Laws
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8. Block M, is on top of block M2 which is on top of a horizontal, frictionless surface. A
horizontal force, F, is applied to M. The coefficient of static friction is µs and the coefficient of
kinetic friction is µk. Find, a) the maximum force that can be applied to M1, such that the position
of Mi relative to M2 will not change. (M1 will not slip on top of M2). Then, if the force acting on
Mi is doubled, or F' = 2F, find the acceleration of each mass.
M,
friction
M2
no friction
Transcribed Image Text:8. Block M, is on top of block M2 which is on top of a horizontal, frictionless surface. A horizontal force, F, is applied to M. The coefficient of static friction is µs and the coefficient of kinetic friction is µk. Find, a) the maximum force that can be applied to M1, such that the position of Mi relative to M2 will not change. (M1 will not slip on top of M2). Then, if the force acting on Mi is doubled, or F' = 2F, find the acceleration of each mass. M, friction M2 no friction
Expert Solution
Step 1

Given:

The mass of the first block is M1.

The mass of the second block is M2.

The horizontal force is F.

The coefficient of static friction is μs.

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