8.As of February 19-25, the 7-day average of percent of positive tests for Covid-19 is 2%. The random variable Xrepresents the number of positive tests in a group of 5 randomly selected tests.XP(x)010.9039220.0+0.0+0.0+Identify each of the following characteristics and fill in the missing values from the distribution:n=p=X=Discuss the three characteristics of the distribution.Shape:Center:Spread:Find the probability of exactly one positive test in a group of 5 randomly selected tests.Find the probability of at least one positive test in a group of 5 randomly selected tests.

When probability of success p remain constant throughout the experiment all trials are independent…

Answered: 8. As of February 19-25, the 7-day…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose X1,., Xn, for n > 1, are sampled independently from a distribution with mean u and variance o?. Consider the following four estimators for X1+ Xn 2 X1 2 п(п + 1) i=1 a. Calculate the bias of each of these estimators. b. Calculate the standard error for each estimator. c. Which estimator would you choose to use? (Give a reason for your choice).
8.64 If S₁² and S₂² represent the variances of independent random samples of size ₁ variances 12 = 10 and 622 = 15, respectively, find P(S12/S2²1.26) 25 and n2 = 31, taken from normal populations with
Two separate samples are selected from the same population. Each have an n=8. Both samples receive a different treatment. After the treatment, the first sample has SS=16 and the second sample has SS=24. With a mean of 3 for the first group and mean of 6 for the second group, compute the t statistic. State the conclusion of these findings.
Suppose that X₁,..., Xn are i.i.d. from a normal population with mean μ and variance o². Calculate the expected value and the variance of the sample mean X and find the distribution of √n(X − µ).
1. Six batteries taken at random from a large lot were subjected to life tests with the following results: 19, 22, 18, 16, 25, and 20 hours. Find the probability that the sample mean of x= 20 hours, as observed here, or one less than 20 hours could arise if the true mean of the lot of batteries is 21.5 hours, assuming a known variance of o = 10 hours, for the individual batteries in the lot. %3D
Consider a regression analysis with n= 51 and four potential independent variables. Suppose that one of the independent variables has a correlation of 0.49 with the dependent variable. Does this imply that this independent variable will have a very small Student's t statistic in the regression analysis with all four predictor variables? Choose all that apply. A. The correlation between the independent variable and the dependent variable could result in a very small Student's t statistic as the correlation creates a high variance. B. Correlation between the independent variable and the dependent variable is not necessarily evidence of a small Student's t statistic. C. A high correlation among the independent variables could result in a very small Student's t statistic as the correlation increases the coefficient standard errors. D. Correlation between the independent variable and the dependent variable is evidence of a small Student's t statistic.
the data support the claim that the average ACT composite score of students from this students is randomly selected from a local high school with an X = 23 and s = 5.2. Do ACT composite scores are normally distributed with a u = 21. A sample of 25 students is randomly selected from a local high school with an X= 23 and s =5.L.D high school is different than 21 on the ACT composite score, using x = .05?
Workers' Distractions. A recent study showed that the modern working person experiences an average of 2.1 hours per day of distractions (phone calls, e- mails, impromptu visits, etc.). A random sample of 16 workers for a large corporation found that these workers were distracted an average of 1.8 hours per day and the standard deviation was 20 minutes. Estimate the true mean population distraction time with 90% confidence, and compare your answer to the results of the study. (1.654,1.946). Mean of the study is outside or "different" from the result of our study.

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