8. a. Draw the arrows for each step of the mechanism shown below; b. List which one of the 4 basic mechanisms is demonstrated in each step A-D: de B... B.. C :Br + Step A: Step B: Step C: Step D: A H 8 + 7 + HBr :

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**Question 8**

**a. Draw the arrows for each step of the mechanism shown below;**  
**b. List which one of the 4 basic mechanisms is demonstrated in each step A-D:**

---

**Reaction Mechanism Diagram:**

1. **Step A:**
   - A cyclopentene molecule with a bromine atom attached is shown. The bromine atom has a lone pair of electrons and leaves, resulting in a positively charged cyclopentene and a bromide ion.

2. **Step B:**
   - The positively charged cyclopentene ion and bromide ion are present.

3. **Step C:**
   - The positively charged cyclopentene reacts with a molecule of ethanol (showing lone pairs on the oxygen), resulting in a new intermediate where the ethoxy group is attached to the cyclopentane, and a proton is still present on the oxygen.

4. **Step D:**
   - The intermediate from Step C then loses a proton (H^+) to form an ether group (oxygen with two lone pairs attached to the cyclopentene) and releases HBr.

**Mechanism Steps Identification:**

- **Step A:** ______________________
- **Step B:** ______________________
- **Step C:** ______________________
- **Step D:** ______________________

(Note: The user is expected to fill in the blanks for each step with the appropriate basic mechanisms such as substitution, elimination, addition, or rearrangement.)
Transcribed Image Text:**Question 8** **a. Draw the arrows for each step of the mechanism shown below;** **b. List which one of the 4 basic mechanisms is demonstrated in each step A-D:** --- **Reaction Mechanism Diagram:** 1. **Step A:** - A cyclopentene molecule with a bromine atom attached is shown. The bromine atom has a lone pair of electrons and leaves, resulting in a positively charged cyclopentene and a bromide ion. 2. **Step B:** - The positively charged cyclopentene ion and bromide ion are present. 3. **Step C:** - The positively charged cyclopentene reacts with a molecule of ethanol (showing lone pairs on the oxygen), resulting in a new intermediate where the ethoxy group is attached to the cyclopentane, and a proton is still present on the oxygen. 4. **Step D:** - The intermediate from Step C then loses a proton (H^+) to form an ether group (oxygen with two lone pairs attached to the cyclopentene) and releases HBr. **Mechanism Steps Identification:** - **Step A:** ______________________ - **Step B:** ______________________ - **Step C:** ______________________ - **Step D:** ______________________ (Note: The user is expected to fill in the blanks for each step with the appropriate basic mechanisms such as substitution, elimination, addition, or rearrangement.)
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