8.) A container holds 15 L of 3.00 mol of diatomic gas at a pressure of 8 atm and 298 K. If the gas expands adiabatically and reversibly to a pressure of 1 atm which of the following is the work done by the expansion. A.) -11.0 kJ B.) +11.0 kJ C.) +8.32 kJ D.) -8.32 kJ E.) 0 kJ 9.) An ideal gas in a container was allowed to expand isothermally against a constant external pressure. Which of the following is the heat transfer and the work done by the system? C.) q = -w = pAV %3D A.) q = -w = nRT In (Vt/Vi) %3D B.) q = 0, w = -nRT In (Vf/Vi) D.) q = nRT In (Vi/Vi), w = 0

8.) A container holds 15 L of 3.00 mol of diatomic gas at a pressure of 8 atm and 298 K. If the gas expands adiabatically and reversibly to a pressure of 1 atm which of the following is the work done by the expansion. A.) -11.0 kJ B.) +11.0 kJ C.) +8.32 kJ D.) -8.32 kJ E.) 0 kJ 9.) An ideal gas in a container was allowed to expand isothermally against a constant external pressure. Which of the following is the heat transfer and the work done by the system? C.) q = -w = pAV %3D A.) q = -w = nRT In (Vt/Vi) %3D B.) q = 0, w = -nRT In (Vf/Vi) D.) q = nRT In (Vi/Vi), w = 0

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

100%

8.) A container holds 15 L of 3.00 mol of diatomic gas at a pressure of 8 atm and 298 K. If the gas
expands adiabatically and reversibly to a pressure of 1 atm which of the following is the work done
by the expansion.
A.) -11.0 kJ
B.) +11.0 kJ
C.) +8.32 kJ
D.) -8.32 kJ
E.) 0 kJ
9.) An ideal gas in a container was allowed to expand isothermally against a constant external
pressure. Which of the following is the heat transfer and the work done by the system?
A.) q = -w = nRT In (Vf/Vi)
C.) q = -w = pAV
%3D
B.) q = 0, w = -nRT In (Vf/Vi)
D.) q = nRT In (Vi/Vi), w = 0

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