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8) wnat is tne name of the first product in the reaction shown below?

8) wnat is tne name of the first product in the reaction shown below?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Homework #16:** **Question 8:** What is the name of the first product in the reaction shown below? The reaction involves the following chemical structures: - A reactant composed of a six-carbon chain with a ketone (C=O) group bonded to the second carbon and a hydroxyl group (OH) connected to the same carbon. - An oxygen molecule (O₂) with two hydrogen atoms. - An equilibrium arrow (⇌) indicating a reversible reaction. - A product that has a six-carbon chain with a positively charged oxygen (O⁺) on the second carbon and the remnants of a water molecule (O with three hydrogen atoms around it) with a positive charge. This reaction appears to illustrate an organic chemistry transformation involving a ketone and an acid or permissive acidic condition to form a carbocation intermediate.
Transcribed Image Text:**Homework #16:** **Question 8:** What is the name of the first product in the reaction shown below? The reaction involves the following chemical structures: - A reactant composed of a six-carbon chain with a ketone (C=O) group bonded to the second carbon and a hydroxyl group (OH) connected to the same carbon. - An oxygen molecule (O₂) with two hydrogen atoms. - An equilibrium arrow (⇌) indicating a reversible reaction. - A product that has a six-carbon chain with a positively charged oxygen (O⁺) on the second carbon and the remnants of a water molecule (O with three hydrogen atoms around it) with a positive charge. This reaction appears to illustrate an organic chemistry transformation involving a ketone and an acid or permissive acidic condition to form a carbocation intermediate.
Expert Solution
Step 1

Here in this reaction 

The reactant is 4-Methylpentanoic acid 

And in this reaction the acid release one proton to the water molecule and itself converted into 4-Methylpentanoate and hydronium ions (H3O+). 

Here in this reaction simple acid base reaction takes place where 4-Methylpentanoic acid act as acid and water is a base and after reaction acid converted into it's conjugate base that is 4-Methylpentanoate and H3O+ 

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