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[8] This exercise is about the bit-wise operators in C. Complete each function skeleton using only straight-line code (i.e., no loops, conditionals, or function calls) and limited of C arithmetic and logical C operators. Specifically, you are only allowed to use the following eight operators: ! ~, &, |, + <<>>. For more details on the Bit-Level Integer Coding Rules on p. 128/129 of the text. A specific problem may restrict the list further: For example, to write a function to compute the bitwise xor of x and y, only using & |, int bitXor(int x, int y) { return ((x&~y) | (~x & y));} (а) /* copyLSbit:Set all bits of result to least significant bit of x * Example: copyLSB(5) = 0×FFFFFFFF, copyLSB(6) = 0x00000000 * Legal ops: */ ! ~ & | + <<>> int copyLSbit(int x) { return 2;} (b) /* negate - return -x * Example: negate(1) = -1. * Legal ops: ! */ int negate(int x) { return 2; } | + <<>> (c) /* isEqual * Examples: isEqual (5,5) * Legal ops: */ int isEqual(int x, int v) { return 2; } y, and 0 otherwise = 1, isEqual(4,5) = 0 return 1 if x == ! ~ & | + <<>>

[8] This exercise is about the bit-wise operators in C. Complete each function skeleton using only straight-line code (i.e., no loops, conditionals, or function calls) and limited of C arithmetic and logical C operators. Specifically, you are only allowed to use the following eight operators: ! ~, &, |, + <<>>. For more details on the Bit-Level Integer Coding Rules on p. 128/129 of the text. A specific problem may restrict the list further: For example, to write a function to compute the bitwise xor of x and y, only using & |, int bitXor(int x, int y) { return ((x&~y) | (~x & y));} (а) /* copyLSbit:Set all bits of result to least significant bit of x * Example: copyLSB(5) = 0×FFFFFFFF, copyLSB(6) = 0x00000000 * Legal ops: */ ! ~ & | + <<>> int copyLSbit(int x) { return 2;} (b) /* negate - return -x * Example: negate(1) = -1. * Legal ops: ! */ int negate(int x) { return 2; } | + <<>> (c) /* isEqual * Examples: isEqual (5,5) * Legal ops: */ int isEqual(int x, int v) { return 2; } y, and 0 otherwise = 1, isEqual(4,5) = 0 return 1 if x == ! ~ & | + <<>>

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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[8] This exercise is about the bit-wise operators in C. Complete each function skeleton using only straight-line code (i.e., no loops, conditionals, or function calls) and limited of C arithmetic and logical C operators. Specifically, you are only allowed to use the following eight operators: ! ~, &, |, + <<>>. For more details on the Bit-Level Integer Coding Rules on p. 128/129 of the text. A specific problem may restrict the list further: For example, to write a function to compute the bitwise xor of x and y, only using & |, int bitXor(int x, int y) { return ((x&~y) | (~x & y));} (a) /* copyLSbit:Set all bits of result to least significant bit of x * Example: copyLSB(5) = 0XFFFFFFFF, copyLSB(6) = 0x00000000 * Legal ops: */ ! & | + <<>> int copyLSbit(int x) { return 2;} (b) /* negate - return -x * Example: negate(1) = -1. * Legal ops:! */ int negate(int x) { return 2; } | + <<>> (c) /* isEqual * Examples: isEqual (5,5) * Legal ops: */ int isEqual(int x, int y) { return 2; } return 1 if x == y, and 0 otherwise = 1, isEqual(4,5) = 0 | + <<>> ! &
Transcribed Image Text:[8] This exercise is about the bit-wise operators in C. Complete each function skeleton using only straight-line code (i.e., no loops, conditionals, or function calls) and limited of C arithmetic and logical C operators. Specifically, you are only allowed to use the following eight operators: ! ~, &, |, + <<>>. For more details on the Bit-Level Integer Coding Rules on p. 128/129 of the text. A specific problem may restrict the list further: For example, to write a function to compute the bitwise xor of x and y, only using & |, int bitXor(int x, int y) { return ((x&~y) | (~x & y));} (a) /* copyLSbit:Set all bits of result to least significant bit of x * Example: copyLSB(5) = 0XFFFFFFFF, copyLSB(6) = 0x00000000 * Legal ops: */ ! & | + <<>> int copyLSbit(int x) { return 2;} (b) /* negate - return -x * Example: negate(1) = -1. * Legal ops:! */ int negate(int x) { return 2; } | + <<>> (c) /* isEqual * Examples: isEqual (5,5) * Legal ops: */ int isEqual(int x, int y) { return 2; } return 1 if x == y, and 0 otherwise = 1, isEqual(4,5) = 0 | + <<>> ! &
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