8 Show why reaction is spontaneous only hure, while reaction (a) is always at low tempre non spontaneous a) CH4 (g) + 20₂(g) → 2 H₂O (l) + CO₂ (g) (endothermic) b) 2C₂H6 (g) +702(g) → 6 H₂0 (e) + 4 (0₂ (g) (@xothermic)

Principles of Modern Chemistry
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Chapter13: Spontaneous Processes And Thermodynamic Equilibrium
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**Understanding Reaction Spontaneity Based on Temperature: An Explanation with Examples**

**Objective:** 
To demonstrate why certain chemical reactions are spontaneous at low temperatures while others are non-spontaneous regardless of temperature.

**Reactions:**
(a) \( \text{CH}_4 (\text{g}) + 2\text{O}_2 (\text{g}) \rightarrow 2\text{H}_2\text{O} (\text{l}) + \text{CO}_2 (\text{g}) \) 

(b) \( 2\text{C}_2\text{H}_6 (\text{g}) + 7\text{O}_2 (\text{g}) \rightarrow 6\text{H}_2\text{O} (\text{l}) + 4\text{CO}_2 (\text{g}) \) (exothermic)

**Problem:**
Show why reaction (b) is spontaneous only at low temperatures, while reaction (a) is always non-spontaneous.

### Explanation:

**1. Reaction Equations:**
   - **Reaction (a):**
     \[
     \text{CH}_4 (\text{g}) + 2\text{O}_2 (\text{g}) \rightarrow 2\text{H}_2\text{O} (\text{l}) + \text{CO}_2 (\text{g})
     \]
   - **Reaction (b):**
     \[
     2\text{C}_2\text{H}_6 (\text{g}) + 7\text{O}_2 (\text{g}) \rightarrow 6\text{H}_2\text{O} (\text{l}) + 4\text{CO}_2 (\text{g}) \, (\text{{exothermic}})
     \]

**2. Enthalpy (ΔH) and Entropy (ΔS) considerations:**
   - **Exothermic Reactions:** These reactions release heat, denoted by a negative ΔH.
   - **Endothermic Reactions:** These reactions absorb heat, denoted by a positive ΔH.

   For spontaneity:
   - Spontaneous at all temperatures: ΔG = ΔH - TΔS < 0 when ΔH is negative and ΔS positive.
   - Spontaneous at low temperatures: When
Transcribed Image Text:**Understanding Reaction Spontaneity Based on Temperature: An Explanation with Examples** **Objective:** To demonstrate why certain chemical reactions are spontaneous at low temperatures while others are non-spontaneous regardless of temperature. **Reactions:** (a) \( \text{CH}_4 (\text{g}) + 2\text{O}_2 (\text{g}) \rightarrow 2\text{H}_2\text{O} (\text{l}) + \text{CO}_2 (\text{g}) \) (b) \( 2\text{C}_2\text{H}_6 (\text{g}) + 7\text{O}_2 (\text{g}) \rightarrow 6\text{H}_2\text{O} (\text{l}) + 4\text{CO}_2 (\text{g}) \) (exothermic) **Problem:** Show why reaction (b) is spontaneous only at low temperatures, while reaction (a) is always non-spontaneous. ### Explanation: **1. Reaction Equations:** - **Reaction (a):** \[ \text{CH}_4 (\text{g}) + 2\text{O}_2 (\text{g}) \rightarrow 2\text{H}_2\text{O} (\text{l}) + \text{CO}_2 (\text{g}) \] - **Reaction (b):** \[ 2\text{C}_2\text{H}_6 (\text{g}) + 7\text{O}_2 (\text{g}) \rightarrow 6\text{H}_2\text{O} (\text{l}) + 4\text{CO}_2 (\text{g}) \, (\text{{exothermic}}) \] **2. Enthalpy (ΔH) and Entropy (ΔS) considerations:** - **Exothermic Reactions:** These reactions release heat, denoted by a negative ΔH. - **Endothermic Reactions:** These reactions absorb heat, denoted by a positive ΔH. For spontaneity: - Spontaneous at all temperatures: ΔG = ΔH - TΔS < 0 when ΔH is negative and ΔS positive. - Spontaneous at low temperatures: When
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