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8 Reciprocal. 1/z, solve 1/(3 + j8) Note: If the given denominator is in polar form, just reverse the angle direction, example 1/(5<45°) = 0.2<-45° 0.041 -j0.11 0.14<-85.50° 0.14 + j0.12 NFTOC 0.011 -j0.14 0.18<40.60° 0.11<-69.44°

8 Reciprocal. 1/z, solve 1/(3 + j8) Note: If the given denominator is in polar form, just reverse the angle direction, example 1/(5<45°) = 0.2<-45° 0.041 -j0.11 0.14<-85.50° 0.14 + j0.12 NFTOC 0.011 -j0.14 0.18<40.60° 0.11<-69.44°

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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#8 Please choose the correct answer. Show your solutions.
8 Reciprocal. 1/z, solve 1/(3 + j8) Note: If the given denominator is in polar form, just reverse the angle direction, example 1/(5<45°) = 0.2<-45° 0.041 -j0.11 0.14<-85.50° 0.14 + j0.12 NFTOC 0.011 -j0.14 0.18<40.60° 0.11<-69.44°
Transcribed Image Text:8 Reciprocal. 1/z, solve 1/(3 + j8) Note: If the given denominator is in polar form, just reverse the angle direction, example 1/(5<45°) = 0.2<-45° 0.041 -j0.11 0.14<-85.50° 0.14 + j0.12 NFTOC 0.011 -j0.14 0.18<40.60° 0.11<-69.44°
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