8 In the differential amplifier shown in Figure P8.87, Vsz = 9 mV 13 mV Vo = Vc + vad Voc = 33 mV (common-mode output voltage) Vod = 18 V (differential-mode output voltage) Determine a. The common-mode gain. b. The differential-mode gain. c. The common-mode rejection ratio in decibels. ww- R3 Vo R. ww- R4 R2 'S2 (+
8 In the differential amplifier shown in Figure P8.87, Vsz = 9 mV 13 mV Vo = Vc + vad Voc = 33 mV (common-mode output voltage) Vod = 18 V (differential-mode output voltage) Determine a. The common-mode gain. b. The differential-mode gain. c. The common-mode rejection ratio in decibels. ww- R3 Vo R. ww- R4 R2 'S2 (+
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
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Expert Solution
Step 1
In the differential amplifier shown has VS1 = 13mV and VS2 =9mV. As the above configuration has both types of feedback positive and negative. So here virtual ground concept not applicable.
Part (A):-
To determine the common-mode gain of the above op-amp is determined by the relation.
Therefore, the output voltage is given as,
Step 2
Output voltage in term of gain can be written as,
The general expression of the output voltage is,
Hence, the common-mode gain is evaluated by,
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