b. E2 R3 Figure 1: 1. In figure 1 Kirchhoff's rules read: -12 R2 - €1 + IR1 - €2 = 0 (a) : €2 - I1 R1 - I3 R3 = 0 (True, False) I3 = I1 + 12 R3+e2 R3+e2 R2 R1 R2+R2R3+R3R1 Rj+jR3+e2 R3 RIR2+R2R3+R3R1 €2 R2- R I = (b) : I2 = (True, False) 13 = (c) : Va - Va = -13 R3 = €1 + 12 R2 = I R1 - €2 (True, False) (d) The direction of the current I2 is opposite of what is assumed in the figure (True, False) (e) If e1 = 12V ; €2 = 10V ; RỊ = 0.012; R2 = 1N ; and R3 = .06N , then |I1| = 171.7A ; |I2| = .3A ; and |13| = 171.4A (True, False) (f) For the same numerical values given in part (e) the energy released by the battery, 1, for a time interval of 1.5 second is : Energye = (I1)t = 3090.5J (True, False)
b. E2 R3 Figure 1: 1. In figure 1 Kirchhoff's rules read: -12 R2 - €1 + IR1 - €2 = 0 (a) : €2 - I1 R1 - I3 R3 = 0 (True, False) I3 = I1 + 12 R3+e2 R3+e2 R2 R1 R2+R2R3+R3R1 Rj+jR3+e2 R3 RIR2+R2R3+R3R1 €2 R2- R I = (b) : I2 = (True, False) 13 = (c) : Va - Va = -13 R3 = €1 + 12 R2 = I R1 - €2 (True, False) (d) The direction of the current I2 is opposite of what is assumed in the figure (True, False) (e) If e1 = 12V ; €2 = 10V ; RỊ = 0.012; R2 = 1N ; and R3 = .06N , then |I1| = 171.7A ; |I2| = .3A ; and |13| = 171.4A (True, False) (f) For the same numerical values given in part (e) the energy released by the battery, 1, for a time interval of 1.5 second is : Energye = (I1)t = 3090.5J (True, False)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please do 1 D, E, and F
**Explanation of Diagram:**
The diagram shows a circuit containing two voltage sources (\(\varepsilon_1\) and \(\varepsilon_2\)), three resistors (\(R_1\), \(R_2\), \(R_3\)), and three current paths (\(I_1\), \(I_2\), \(I_3\)). The circuit is laid out with nodes labeled \(a\), \(b\), \(c\), \(d\), \(e\), and \(f\).
---
**1. Kirchhoff's Rules in the Circuit:**
(a) Given by:
\[
\begin{cases}
-I_2R_2 - \varepsilon_1 + I_1R_1 - \varepsilon_2 = 0 \\
\varepsilon_2 - I_1R_1 - I_3R_3 = 0 \\
I_3 = I_1 + I_2
\end{cases}
\]
- Statements to evaluate as true or false.
(b) Solutions for currents:
\[
\begin{cases}
I_1 = \frac{\varepsilon_1R_3 + \varepsilon_2R_2 + \varepsilon_2R_3}{R_1R_2 + R_2R_3 + R_3R_1}\\
I_2 = \frac{-\varepsilon_1R_1 + \varepsilon_1R_3 + \varepsilon_2R_3}{R_1R_2 + R_2R_3 + R_3R_1}\\
I_3 = \frac{\varepsilon_2R_2 - \varepsilon_1R_1}{R_1R_2 + R_2R_3 + R_3R_1}
\end{cases}
\]
- Statements to evaluate as true or false.
(c) Voltage across \(V_a - V_d\):
\[V_a - V_d = -I_3R_3 = \varepsilon_1 + I_2R_2 = I_1R_1 - \varepsilon_2\]
- Statements to evaluate as true or false.
(d) The direction of the current \(I_2\](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90ba196a-a4da-4c5b-97fd-f3d58be17337%2F90d825c9-e072-43c2-a731-8f121d5ad576%2Fnlsyxa2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website:**
---
**Figure 1:**
**Explanation of Diagram:**
The diagram shows a circuit containing two voltage sources (\(\varepsilon_1\) and \(\varepsilon_2\)), three resistors (\(R_1\), \(R_2\), \(R_3\)), and three current paths (\(I_1\), \(I_2\), \(I_3\)). The circuit is laid out with nodes labeled \(a\), \(b\), \(c\), \(d\), \(e\), and \(f\).
---
**1. Kirchhoff's Rules in the Circuit:**
(a) Given by:
\[
\begin{cases}
-I_2R_2 - \varepsilon_1 + I_1R_1 - \varepsilon_2 = 0 \\
\varepsilon_2 - I_1R_1 - I_3R_3 = 0 \\
I_3 = I_1 + I_2
\end{cases}
\]
- Statements to evaluate as true or false.
(b) Solutions for currents:
\[
\begin{cases}
I_1 = \frac{\varepsilon_1R_3 + \varepsilon_2R_2 + \varepsilon_2R_3}{R_1R_2 + R_2R_3 + R_3R_1}\\
I_2 = \frac{-\varepsilon_1R_1 + \varepsilon_1R_3 + \varepsilon_2R_3}{R_1R_2 + R_2R_3 + R_3R_1}\\
I_3 = \frac{\varepsilon_2R_2 - \varepsilon_1R_1}{R_1R_2 + R_2R_3 + R_3R_1}
\end{cases}
\]
- Statements to evaluate as true or false.
(c) Voltage across \(V_a - V_d\):
\[V_a - V_d = -I_3R_3 = \varepsilon_1 + I_2R_2 = I_1R_1 - \varepsilon_2\]
- Statements to evaluate as true or false.
(d) The direction of the current \(I_2\
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