(8) Find the value of c guaranteed by the Mean Value Theorem for f(x) = 2/²/²/1 I [3, 5]. (A) 1+ 2√2 (B) 2√2 (C)1-2√√/2 (D) 3 on the interval

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(8) Find the value of c guaranteed by the Mean Value Theorem for f(x)
[3, 5].
(A) 1+ 2√2
(B) 2√2
(C)1-2√2
For Questions 9-10, consider a particle whose motion is represented by the position function
s(t) = t²-t, t≥ 0, where s is in feet and t is in seconds.
(9) The particle moves forward when
(A) t > 2
(B)t>1
(D) 3
(A) s(2) — s(0) = 2 ft.
(C) s(2) s() = 2/1/1
2²/1
(10) The distance traveled by the particle in the first two seconds
1
(C)t>
(C)t> ½ (D) It always moves backward.
2
on the interval
(B) |s(2) — s( ½|+|s() - s(0)| = 2/2 + 1/2 = 2/1/2
(D) cannot be determined
Transcribed Image Text:(8) Find the value of c guaranteed by the Mean Value Theorem for f(x) [3, 5]. (A) 1+ 2√2 (B) 2√2 (C)1-2√2 For Questions 9-10, consider a particle whose motion is represented by the position function s(t) = t²-t, t≥ 0, where s is in feet and t is in seconds. (9) The particle moves forward when (A) t > 2 (B)t>1 (D) 3 (A) s(2) — s(0) = 2 ft. (C) s(2) s() = 2/1/1 2²/1 (10) The distance traveled by the particle in the first two seconds 1 (C)t> (C)t> ½ (D) It always moves backward. 2 on the interval (B) |s(2) — s( ½|+|s() - s(0)| = 2/2 + 1/2 = 2/1/2 (D) cannot be determined
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