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8) At a large spikeball tournament, the length of time of each rally, in seconds, is normally distributed with mean and standard deviation o. It is found that 4% of the rallies take fewer than 5 seconds, and 70% of the rallies take fewer than 20 seconds. Find the values of µ and o. Solution? Using the inverse normal function, we calculate the z-scores. We set the areas to 0.04 and 0.7. In both cases we let u = 0,0 = 1. The two z-scores are –1.750686 .. and 0.524400. = -1.750686 .. We set up a system of equations: 20-u = 0.524400 ... Solving using technology, we find µ = 6.59 and o = 16.5

8) At a large spikeball tournament, the length of time of each rally, in seconds, is normally distributed with mean and standard deviation o. It is found that 4% of the rallies take fewer than 5 seconds, and 70% of the rallies take fewer than 20 seconds. Find the values of µ and o. Solution? Using the inverse normal function, we calculate the z-scores. We set the areas to 0.04 and 0.7. In both cases we let u = 0,0 = 1. The two z-scores are –1.750686 .. and 0.524400. = -1.750686 .. We set up a system of equations: 20-u = 0.524400 ... Solving using technology, we find µ = 6.59 and o = 16.5

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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8) At a large spikeball tournament, the length of time of each rally, in seconds, is normally distributed with mean u and standard deviation o. It is found that 4% of the rallies take fewer than 5 seconds, and 70% of the rallies take fewer than 20 seconds. Find the values of µ and o. Solution? Using the inverse normal function, we calculate the z-scores. We set the areas to 0.04 and 0.7. In both cases we let u = 0,0 = 1. The two z-scores are – 1.750686 . and 0.524400 . 5-H -1.750686 . We set up a system of equations: 20-u = 0.524400 ... Solving using technology, we find u z 6.59 and o z 16.5
Transcribed Image Text:8) At a large spikeball tournament, the length of time of each rally, in seconds, is normally distributed with mean u and standard deviation o. It is found that 4% of the rallies take fewer than 5 seconds, and 70% of the rallies take fewer than 20 seconds. Find the values of µ and o. Solution? Using the inverse normal function, we calculate the z-scores. We set the areas to 0.04 and 0.7. In both cases we let u = 0,0 = 1. The two z-scores are – 1.750686 . and 0.524400 . 5-H -1.750686 . We set up a system of equations: 20-u = 0.524400 ... Solving using technology, we find u z 6.59 and o z 16.5
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