10.18 a) Find the average power, the reactive power, andPSPICEMULTISIMthe apparent power supplied by the voltage sourcein the circuit in Fig. P10.18 if vg = 40 cos 10°t V.b) Check your answer in (a) by showingPdev = Σ Pabsanswer in (a) by showingc) Check yourdev = abs.Figure P10.18V8876 W008+40 Ωwww25 nFHE80 ΜΗ60 ΩVelow

8 a) Find the average power, the reactive power, and the apparent power supplied by the voltage source in the circuit in Fig. P10.18 if vg = 40 cos 10ºt V. answer in (a) by showing 8 M b) Check your Pdev Pabs c) Check your answer in (a) by showing dev = abs. = Figure P10.18 co W002 40 Ω 25 nF HE 80 ΜΗ 60 Ω

8 a) Find the average power, the reactive power, and the apparent power supplied by the voltage source in the circuit in Fig. P10.18 if vg = 40 cos 10ºt V. answer in (a) by showing 8 M b) Check your Pdev Pabs c) Check your answer in (a) by showing dev = abs. = Figure P10.18 co W002 40 Ω 25 nF HE 80 ΜΗ 60 Ω

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

A farm house is located at the end of a country road in northern Michigan. The Thévenin impedance seen looking back into the power line from the electrical distribution panel is 0.2+j0.2 Ω. The Thévenin voltage is 240 V rms 60 Hz ac. A 2-hp 240-V-rms capacitor-start motor is used for pumping water. We want to estimate the voltage drop observed in the house when the motor starts. Typically, such a motor has a power factor of 75 percent and an efficiency of 80 percent at full load. Also, the starting current can be estimated as six times the full-load current. Estimate the worst-case percentage voltage drop observed when the motor starts.
Calculate the active power, reactive power, power factor, Reactive factor if: v=100 cos (wt+150) V and i=4 cos (wt-1050) V Note: Enter the angle in radians. (rad * pi/180) Consider V and I given in the problem represents Vrms and Irms Active Power, P = Vrms Irms cos(θv – θi) Reactive Power, Q = Vrms Irms sin(θv – θi) Power factor (pf) = cos(θv – θi) Reactive factor (rf) = sin(θv – θi)
Determine the power and the rms value of: (a) 8(t) = C cos (wot + 0) (b) g(t) = C1 cos (wt + 01) + C2 cos(@zt + 02) (c) wi 7 w2 8(t) = Dejaot
1.12 A sensor producing a voltage of 1 V rms with a source resistance of 1 MQ is available to drive a 10- load. If connected directly, what voltage and power levels result at the load? If a unity-gain (i.e., Avo = 1) buffer amplifier with 1- MN input resistance and 10-№ output resistance is interposed between source and load, what do the output voltage and power levels become? For the new arrangement, find the voltage gain from source to load, and the power gain (both expressed in decibels).
Help me please IN THE CIRCUIT SHOWN, THE VALUE OF THE CURRENT SOURCE IS IN RMS VALUE. DETERMINE: A) THE VOLTAGE (ONLY THE MAGNITUDE) AT THE INDUCTOR TERMINALS, VL B) THE VOLTAGE (ONLY THE MAGNITUDE) AT THE RESISTOR TERMINALS, VR C) THE AVERAGE POWER ABSORBED BY THE 40 Ω RESISTOR
Problem 10.40 The sinusoidal voltage source in the circuit in the figure is developing an rms voltage of 2000 V. The R₂ = 6 2 load in the circuit is absorbing four times as much average power as the R₁ = 232 load. The two loads are matched to the sinusoidal source that has an internal impedance of 500 20° 2. (Figure 1) Figure 500 ΩΣ 2000/0°+ V (rms) a₁:1 Ideal a2:1 || Ideal 1 of 1 R₁ R₂
For the circuit shown, what is the average power, Py, consumed by the 1+j5 2 load impedance? (Assume the current source is in RMS.) 2Ω 10 Is = 3 20° A -j10 j5 0 19.04 W O 8.70 W 1.80 W O 0.84 W ww
Can I have help with problem 10.48?
Your Question: Use the following values for the components: Constants I1 = 4 ∠0° [A] I2 = 6 ∠90° [A] ω = 2 000 [rad/s] R1 = 4 [Ω] R2 = 6 [Ω] Randomized L = 1,6 [mH] C = 79 [μF] Use Nodal Analysis to find the rms voltage across the resistor R1, answer in [V] with one decimal.
The equations of current in two parallel-connected electric devices are i, = 171.3 sin(377t + 45°) and iz = 8.5 sin (377t – 45°). what is the RMS value of the resultant current? Оа. 10.67 аmp. Ob. 7.54 amp Ос. 19.8 amр. O d. 14 amp.
Please show all st
Circuit Diagram V1 R1 220 Vrms 50 Q 60 Hz 0° L1 100mH Computed Values Compute the expected power factor of the circuit given the different capacitance. Reactive IT (RMS) Power Capacitance Real Power (UF) Power (Watts) Factor (Vars) mag (A) 100 90 80 70 60 50 40 30 20 10 C1 100uF