A farm house is located at the end of a country road in northern Michigan. The Thévenin impedance seen looking back into the power line from the electrical distribution panel is 0.2+j0.2 Ω. The Thévenin voltage is 240 V rms 60 Hz ac. A 2-hp 240-V-rms capacitor-start motor is used for pumping water. We want to estimate the voltage drop observed in the house when the motor starts. Typically, such a motor has a power factor of 75 percent and an efficiency of 80 percent at full load. Also, the starting current can be estimated as six times the full-load current. Estimate the worst-case percentage voltage drop observed when the motor starts.

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A farm house is located at the end of a country road in northern Michigan. The Thévenin impedance seen looking back into the power line from the electrical distribution panel is 0.2+j0.2 Ω. The Thévenin voltage is 240 V rms 60 Hz ac. A 2-hp 240-V-rms capacitor-start motor is used for pumping water. We want to estimate the voltage drop observed in the house when the motor starts. Typically, such a motor has a power factor of 75 percent and an efficiency of 80 percent at full load. Also, the starting current can be estimated as six times the full-load current. Estimate the worst-case percentage voltage drop observed when the motor starts.

Expert Solution
Step 1

Given data:

Pout=2 hpVrms=240 V

The expression for the output power is given as,

Pout=2 hp=2×746=1492 W

The expression for the input power is given as,

%η=PoutPin×10080=1492Pin×100Pin=1865 W

Step 2

Now the expression for the current is given as,

I=PinVcosθ=1865240×0.75=10.36 A

The expression for the starting current is given as,

Is=6I=6×10.36=62.16 A

Electrical Engineering homework question answer, step 2, image 1

Calculating thevenin's impedance,

Zth=0.2+0.2j=0.22+0.22-tan-10.20.2=0.283-45°

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