8) A certain photochemical process has fluorescence lifetime of tr= 10-10s and internal conversion rate constant of ke 10° s. Assuming that the rate constants for the intersystem crossing and quenching are sufficiently small so that these processes can be neglected, calculate a) the rate constant for the deactivation of the excited state by fluorescence. kr= b) the fluorescence quantum yield. Workouts

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Constants
Ideal gas constant:
= 8.314 J K mol-
= 0.083 dm bar K mol
= 0.082 dm atm K mol
Avogadro's constant: NA = 6.022x1023 mol-!
Boltzmann constant: k 1.38x1023 J K
Speed of light:
c = 3 x 10% m s
Planck's constant:
h = 6.626x1034 J s
1 bar = 105 Pa
1 atm = 101325 Pa
Relations
U = NKT²(n
= + k In Q
S =
%3D
A = -kT In Q
G = -NkT In)
R.
Transcribed Image Text:Constants Ideal gas constant: = 8.314 J K mol- = 0.083 dm bar K mol = 0.082 dm atm K mol Avogadro's constant: NA = 6.022x1023 mol-! Boltzmann constant: k 1.38x1023 J K Speed of light: c = 3 x 10% m s Planck's constant: h = 6.626x1034 J s 1 bar = 105 Pa 1 atm = 101325 Pa Relations U = NKT²(n = + k In Q S = %3D A = -kT In Q G = -NkT In) R.
8) A certain photochemical process has fluorescence lifetime of tr=10-10 s and internal conversion
rate constant of kie = 10" s . Assuming that the rate constants for the intersystem crossing and
quenching are sufficiently small so that these processes can be neglected, calculate
a)
the rate constant for the deactivation of the excited state by fluorescence. ky=
b)
the fluorescence quantum yield.
Workouts
Transcribed Image Text:8) A certain photochemical process has fluorescence lifetime of tr=10-10 s and internal conversion rate constant of kie = 10" s . Assuming that the rate constants for the intersystem crossing and quenching are sufficiently small so that these processes can be neglected, calculate a) the rate constant for the deactivation of the excited state by fluorescence. ky= b) the fluorescence quantum yield. Workouts
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