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8 A 25kg child sits on a rope swing. The rope has a length of L = 3m. The swing is moved so that it starts with an angle of 0 = 20°, and is released from rest. Looking at the image, the y direction will remained aligned with the string throughout its path. In this case, the acceleration in the y direction is always equal to v²/L, where v is the speed of the child. a. As soon as the swing is released, there is no acceleration in the y direction because the initial speed is 0. Calculate the acceleration in the a direction. (Draw a free body diagram, etc.) b. When the swing is at its lowest point, the swing will be moving with a speed of v = 1.88m/s. Calculate the force that the rope exerts on the swing when the swing is at its lowest point. (Draw another free body diagram, etc.)

8 A 25kg child sits on a rope swing. The rope has a length of L = 3m. The swing is moved so that it starts with an angle of 0 = 20°, and is released from rest. Looking at the image, the y direction will remained aligned with the string throughout its path. In this case, the acceleration in the y direction is always equal to v²/L, where v is the speed of the child. a. As soon as the swing is released, there is no acceleration in the y direction because the initial speed is 0. Calculate the acceleration in the a direction. (Draw a free body diagram, etc.) b. When the swing is at its lowest point, the swing will be moving with a speed of v = 1.88m/s. Calculate the force that the rope exerts on the swing when the swing is at its lowest point. (Draw another free body diagram, etc.)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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8 A 25kg child sits on a rope swing. The rope has a length of L = 3m. The swing is moved so that it starts with an angle of 0 = 20°, and is released from rest. Looking at the image, the y direction will remained aligned with the string throughout its path. In this case, the acceleration in the y direction is always equal to v²/L, where v is the speed of the child. a. As soon as the swing is released, there is no acceleration in the y direction because the initial speed is 0. Calculate the acceleration in the x direction. (Draw a free body diagram, etc.) b. When the swing is at its lowest point, the swing will be moving with a speed of v = 1.88m/s. Calculate the force that the rope exerts on the swing when the swing is at its lowest point. (Draw another free body diagram, etc.)
Transcribed Image Text:8 A 25kg child sits on a rope swing. The rope has a length of L = 3m. The swing is moved so that it starts with an angle of 0 = 20°, and is released from rest. Looking at the image, the y direction will remained aligned with the string throughout its path. In this case, the acceleration in the y direction is always equal to v²/L, where v is the speed of the child. a. As soon as the swing is released, there is no acceleration in the y direction because the initial speed is 0. Calculate the acceleration in the x direction. (Draw a free body diagram, etc.) b. When the swing is at its lowest point, the swing will be moving with a speed of v = 1.88m/s. Calculate the force that the rope exerts on the swing when the swing is at its lowest point. (Draw another free body diagram, etc.)
OANSWERS 1 a. tf 1.27s; b. řf = -6.60mj, tf = 4.00s; c. V; = –3.50mj, ā = %3D 2 half as much 3 they are all the same 4| car 5|a. 0.379m/s²-; b. 0.535m/s²÷; c. 4.17m/s² 6 a. 9.8m/s²1; b. 54.2m/s; c. 5.53s; d. 11.1m; 7 c. 2mm/ms?; d. (-2mm/ms)t + (1mm/ms²)ť²; e. 20.0N; f. (-2mm/ms) + (2mm/ms²)t; g. 2mm/ms; 8 a. 3.35m/s²; b. 275N;
Transcribed Image Text:OANSWERS 1 a. tf 1.27s; b. řf = -6.60mj, tf = 4.00s; c. V; = –3.50mj, ā = %3D 2 half as much 3 they are all the same 4| car 5|a. 0.379m/s²-; b. 0.535m/s²÷; c. 4.17m/s² 6 a. 9.8m/s²1; b. 54.2m/s; c. 5.53s; d. 11.1m; 7 c. 2mm/ms?; d. (-2mm/ms)t + (1mm/ms²)ť²; e. 20.0N; f. (-2mm/ms) + (2mm/ms²)t; g. 2mm/ms; 8 a. 3.35m/s²; b. 275N;
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