8-6 Examples The following creep data were taken on an aluminum alloy at 480C and a constant stress of 2.75 MPa. Plot the data as strain versus time, then determine the steady-state or minimum creep rate. Note: The initial and instantaneous strain is not included. 26 28 1.03 1.12 1.22 8 16 18 20 22 24 30 32 34 10 0.55 Time (min): 0 12 14 0.48 0.62 0.68 0.75 0.82 0.88 0.95 1.36 1.53 1.77

8-6 Examples The following creep data were taken on an aluminum alloy at 480C and a constant stress of 2.75 MPa. Plot the data as strain versus time, then determine the steady-state or minimum creep rate. Note: The initial and instantaneous strain is not included. 26 28 1.03 1.12 1.22 8 16 18 20 22 24 30 32 34 10 0.55 Time (min): 0 12 14 0.48 0.62 0.68 0.75 0.82 0.88 0.95 1.36 1.53 1.77

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

1. For the stress-strain curve shown below, please estimate the properties indicated. (a) Fracture Strain Please do your work on a separate sheet of paper, and put your answers in the boxes on the right. Be sure to include the proper symbol and units. Stress Strain 70 60 50 Stress (ksi) 240 30 20 10 70 0 0.000 60 50 Stress (ksi) 40 20 10 KULL 0 0.000 0.010 0.050 0.100 Strain (in/in) Stress Strain 0.020 0.030 Strain (in/in) 0.040 0.150 0.050 (b) Ultimate Tensile Stress (c) Fracture Stress (d) Proportional Limit (e) Elastic Modulus (1) Yield Stress (g) Tensile Toughness (Modulus of Toughness) (h) Modulus of Resilience
Calculate the young’s modulus from one of these two graphs?
The creep data have been taken on an ahuminum alloy at 400°C and constant stress of 25MPA are shown in below Table, Find the steady state or minimum creep rate. Time (min) strain Time (min) 16 strain 0.135 0.0 0.0 2 0.025 18 0.153 4 0.043 0.065 20 0.172 0.193 0.218 22 0.078 24 10 0.092 26 0.255 12 0.109 28 0.307 14 0.120 30 0.368
What value can not be found from the stress-strain graph? Please select one:a. Modulus of elasticityb. Disgracec. Toughnessd. Poisson ratioe. Yield strength
4) In the temperature range from 600°C to 750°C, a steel wire with 100 mm length shows the steady state creep behavior. The wire was exposed to 600°C under 300 MPa for ten years, how long the specimen would be? ( TH Trung Trong Stress (MPa) 1000 FTTinh Tru Trung Trung Trong th 800 600 400 200 100 80 60 40 815 C 20 d 10-6 104 10-5 650 C 730 C 925°C d d d d d 10-3 10-2 10-1 1 10 10² Steady-state creep rate (h-¹) 10³
Parvinbhai
70% 5. Fatigue data of steel is showed in the following stress-cycle curve. Write down the values of steel endurance limit and steel fatigue strength at 10 cycles in the spaces provided below. 5.1. Steel Endurance Limit: ksi 5.2. Steel Fatigue Strength at 105 cycles: ksi SN Curve 50 45 40 Steel 35 30 Aluminium 20 15 10 10 10 10 10 Number of cycles 10 10 10 Page 5 of 6 (s) ssans
Determine the percentage of ductility of a metal alloy having the following tensile stress-strain diagram. Tensile stress-strain diagram 450 400 350 300 250 200 150 100 NO 50 0.05 0.1 0.15 0.2 0.25 0.3 0 35 0.4 Strain 300 EN Stress (Mpa)
Mild steel 1 Young;s modulus 1219.5 Yield strain and stress (0.4101,500.08) Failure stress and strain :not able to find because the given data shows the experiment did not reach the failure point. if the material stress and strain does not reach a failure point ,what dose it means , does it means that the material is more stronger?
Please don't provide handwitten solution ....
In a laboratory creep experiment at 1273K, a steady-state creep rate of 5 ××10-1 %, per hour is obtained in a metal alloy. The creep mechanism for this alloy is known to be dislocation climb with an activation energy of 200 kJ>mol. Predict the service temperature in (°C) for a creep rate of 8.68 ×10-5 %, per hour. (Assume that the laboratory experiment duplicated the service stress.)
Compute the elongation, in %, of a cylindrical copper rod if it is cold worked such that the diameter is reduced from 15.9 mm to 10.4 mm