+7x-3)+e 2m (2) The value of f sin(5x) cos(3x). dx= A) 1 (3) To evaluate f √x²-49 X (4) The value of f sec tan x tany A) (12x² + 18x + 7) + C B) 2π .dx we substitute x= A)7 sec 0 x tana x dx is C) π D) 0 B) 7sine C) 7tane D) 7cose
+7x-3)+e 2m (2) The value of f sin(5x) cos(3x). dx= A) 1 (3) To evaluate f √x²-49 X (4) The value of f sec tan x tany A) (12x² + 18x + 7) + C B) 2π .dx we substitute x= A)7 sec 0 x tana x dx is C) π D) 0 B) 7sine C) 7tane D) 7cose
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Q 3 please
![(1) f(4x³-9x² + 7x + 3)ex. dx =
A) e *[4x³ + 3x² + 13x + 16) + C
B) -e [4x³ + 3x² + 13x + 16] + C
C) ex (4x³-9x2 +7x+3)-e-*(12x²-18x-7)
+ C
D) -ex (4x³9x²2 +7x-3) + e-*(12x² + 18x + 7) + C
B) 2T
-2m
(2) The value of f sin(5x) cos(3x). dx= A) 1
√√x²-49
(3) To evaluate f
X
(4) The value of f sec4 x tan³ x dx is
+ C B): sec x
A)-
tan x
4
tan x
6
+ +C C)- sec x
sec x
6
+
B
x-2
C) A+ B
(5) The form of the partial fraction decomposition of f(x)
C
D
С
+
x² +25
x² +25
x²+25
Cx+F
Dx+M
Cx+F
x² +25
x² +25
x²+25
Evaluate the following integral f
C
x-2
+
+
+
+
.dx we substitute x = A)7 sec 0
(6)
A) 4 Inx-21-In/x+31+
C) 4 Inx-31-In/x+21+ C
-
B)+
D).
sec x
4 6
+ C
D)
+
(7) √ √²4x dx = A) In | ²2 +2²+ C B) In
x-2
√x²
4x
+
B
x-2
B
+
x X-2
3x+11
x²-x-6
.dx
B) In/x-31-In/x + 2) + C
In (x-3)
+ C
In (x+2)
x-2
2
D) In
+
=
+
+CD)
C) π D) 0
B) 7sine
D
(x²+25)²
DX+M
(x²+25)²
√√x²-4x
2
11x-2x³-4x² +5
x(x-2)(x²+25)²
x- 2
√√x² - 4x
tan x
4
x-2
C) In
2
2
(8) f csc (3x) dx =
A) In |csc (3x) + cot (3x)| + C
C)- In csc (3x)- cot (3x)| + C
B)-In (csc (3x) + cot (3x)| + C
D)- In |csc (3x) + tan (3x)| + C
(9) Find an appropriate choice of u and dv for integration by parts of f(In(x))².dx.
A)u = (Inx)2, dv = dx
B)u = lnx, dv=dx
C)u = lnx, dv=lnx. dx
D)u = x,dv = (lnx)².dx
+ C
C) 7tane D) 7cose
√x²
-
-
2
tan"
6
4x
+ C
+ C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f94b6d9-f121-47bb-9c95-c9aa56b8e52e%2Fcb27379a-35f5-41e5-b6bf-9a30518a33b5%2F6viauwa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(1) f(4x³-9x² + 7x + 3)ex. dx =
A) e *[4x³ + 3x² + 13x + 16) + C
B) -e [4x³ + 3x² + 13x + 16] + C
C) ex (4x³-9x2 +7x+3)-e-*(12x²-18x-7)
+ C
D) -ex (4x³9x²2 +7x-3) + e-*(12x² + 18x + 7) + C
B) 2T
-2m
(2) The value of f sin(5x) cos(3x). dx= A) 1
√√x²-49
(3) To evaluate f
X
(4) The value of f sec4 x tan³ x dx is
+ C B): sec x
A)-
tan x
4
tan x
6
+ +C C)- sec x
sec x
6
+
B
x-2
C) A+ B
(5) The form of the partial fraction decomposition of f(x)
C
D
С
+
x² +25
x² +25
x²+25
Cx+F
Dx+M
Cx+F
x² +25
x² +25
x²+25
Evaluate the following integral f
C
x-2
+
+
+
+
.dx we substitute x = A)7 sec 0
(6)
A) 4 Inx-21-In/x+31+
C) 4 Inx-31-In/x+21+ C
-
B)+
D).
sec x
4 6
+ C
D)
+
(7) √ √²4x dx = A) In | ²2 +2²+ C B) In
x-2
√x²
4x
+
B
x-2
B
+
x X-2
3x+11
x²-x-6
.dx
B) In/x-31-In/x + 2) + C
In (x-3)
+ C
In (x+2)
x-2
2
D) In
+
=
+
+CD)
C) π D) 0
B) 7sine
D
(x²+25)²
DX+M
(x²+25)²
√√x²-4x
2
11x-2x³-4x² +5
x(x-2)(x²+25)²
x- 2
√√x² - 4x
tan x
4
x-2
C) In
2
2
(8) f csc (3x) dx =
A) In |csc (3x) + cot (3x)| + C
C)- In csc (3x)- cot (3x)| + C
B)-In (csc (3x) + cot (3x)| + C
D)- In |csc (3x) + tan (3x)| + C
(9) Find an appropriate choice of u and dv for integration by parts of f(In(x))².dx.
A)u = (Inx)2, dv = dx
B)u = lnx, dv=dx
C)u = lnx, dv=lnx. dx
D)u = x,dv = (lnx)².dx
+ C
C) 7tane D) 7cose
√x²
-
-
2
tan"
6
4x
+ C
+ C
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