-778 KJ Use the following information to determine the enthalpy for the reaction shown below. CH4(g) + H2O(g) → CO(g) + 3H;(g) AH° = ? %3D 2C(s) + 2H2O(g) → CH4(g) + CO2(g) AH° = 15.3 kJ %3D C(s) + H2O(g) → CO(g) + H2(g) AH° = 131.3 kJ %3D CO(g) + H,O(g) → CO2(g) + H2(g) AH° = -41.2 kJ %3D

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-778 KJ
Use the following information to determine the enthalpy for the reaction shown below.
CH4(g) + H2O(g) → CO(g) + 3H;(g)
AH° = ?
%3D
2C(s) + 2H2O(g) → CH4(g) + CO2(g)
AH° = 15.3 kJ
%3D
C(s) + H2O(g) → CO(g) + H2(g)
AH° = 131.3 kJ
%3D
CO(g) + H,O(g) → CO2(g) + H2(g)
AH° = -41.2 kJ
%3D
Transcribed Image Text:-778 KJ Use the following information to determine the enthalpy for the reaction shown below. CH4(g) + H2O(g) → CO(g) + 3H;(g) AH° = ? %3D 2C(s) + 2H2O(g) → CH4(g) + CO2(g) AH° = 15.3 kJ %3D C(s) + H2O(g) → CO(g) + H2(g) AH° = 131.3 kJ %3D CO(g) + H,O(g) → CO2(g) + H2(g) AH° = -41.2 kJ %3D
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