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75 k 40 k Hinge 250 k-ft E A B D F12 ft 12 ft 12 f- -12 ft- El = constant E = 29,000 ksi I= 6,000 in.4 FIG. P6.33, P6.59 2.5 k/ft Hinge 35 k A B -8 ft 8 ft- 16 ft I= 4,000 in.4 I= 3,000 in.4 E = constant = 30,000 ksi FIG. P6.34, P6.60

75 k 40 k Hinge 250 k-ft E A B D F12 ft 12 ft 12 f- -12 ft- El = constant E = 29,000 ksi I= 6,000 in.4 FIG. P6.33, P6.59 2.5 k/ft Hinge 35 k A B -8 ft 8 ft- 16 ft I= 4,000 in.4 I= 3,000 in.4 E = constant = 30,000 ksi FIG. P6.34, P6.60

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Use the conjugate-beam method to determine the slopes and deflections at points B and D of the beams shown in Figs. P6.33 and P6.34.

75 k 40 k Hinge 250 k-ft E A B D F12 ft 12 ft 12 f- -12 ft- El = constant E = 29,000 ksi I= 6,000 in.4 FIG. P6.33, P6.59 2.5 k/ft Hinge 35 k A B -8 ft 8 ft- 16 ft I= 4,000 in.4 I= 3,000 in.4 E = constant = 30,000 ksi FIG. P6.34, P6.60
Transcribed Image Text:75 k 40 k Hinge 250 k-ft E A B D F12 ft 12 ft 12 f- -12 ft- El = constant E = 29,000 ksi I= 6,000 in.4 FIG. P6.33, P6.59 2.5 k/ft Hinge 35 k A B -8 ft 8 ft- 16 ft I= 4,000 in.4 I= 3,000 in.4 E = constant = 30,000 ksi FIG. P6.34, P6.60
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