= 7.35 × 10²2 kg) 36. (II) Find the net force on the Moon (mM due to the gravitational attraction of both the Earth (mẸ = 5.98 × 1024 kg) and the Sun (ms assuming they are at right angles to each other, Fig. 5–43. = 1.99 × 10³0 kg), Мoon МЕ Earth FMS FIGURE 5-43 Problem 36. Orientation of Sun (S), Earth (E), and Moon (M) at right angles to each other (not to scale). Sun

= 7.35 × 10²2 kg) 36. (II) Find the net force on the Moon (mM due to the gravitational attraction of both the Earth (mẸ = 5.98 × 1024 kg) and the Sun (ms assuming they are at right angles to each other, Fig. 5–43. = 1.99 × 10³0 kg), Мoon МЕ Earth FMS FIGURE 5-43 Problem 36. Orientation of Sun (S), Earth (E), and Moon (M) at right angles to each other (not to scale). Sun

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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