= 7.35 × 10²2 kg) 36. (II) Find the net force on the Moon (mM due to the gravitational attraction of both the Earth (mẸ = 5.98 × 1024 kg) and the Sun (ms assuming they are at right angles to each other, Fig. 5–43. = 1.99 × 10³0 kg), Мoon МЕ Earth FMS FIGURE 5-43 Problem 36. Orientation of Sun (S), Earth (E), and Moon (M) at right angles to each other (not to scale). Sun

= 7.35 × 10²2 kg) 36. (II) Find the net force on the Moon (mM due to the gravitational attraction of both the Earth (mẸ = 5.98 × 1024 kg) and the Sun (ms assuming they are at right angles to each other, Fig. 5–43. = 1.99 × 10³0 kg), Мoon МЕ Earth FMS FIGURE 5-43 Problem 36. Orientation of Sun (S), Earth (E), and Moon (M) at right angles to each other (not to scale). Sun

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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2. Consider a satellite that is in geosynchronous orbit around the earth's equator. A geosynchronous orbit is one in Earth which the satellite appears to satellite be stationary overhead for someone looking up at it from Me a point on the equator – some communications satellites are placed in that orbit because of that apparent "stationary" 24 property. The mass of the earth is Me = 5.98 ×10ª kg, and the mass of the satellite m = 100 kg. The radius of the earth is R. = 6.37 × 10°m. The satellite is %3D made of titanium, whose specific heat is 134 J/(kg K) (assume the same for both solid and liquid), the latent heat of fusion is 282.7 kJ/kg, and the melting temperature is 3695K, the boiling temperature is 5828 K. The gravitational constant G = 6.673 × 10" N m²/kg². А. What is the angular velocity of the satellite? В. What is the radius of the orbit of the satellite?
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