12) Two masses, one 7.5 × 109 kg and the other 3.0 × 109 kg, are placed along the x and y axes as shown in the figure below. What is the net gravitational force (magnitude and angle from x-axis) on the 1.2 x 109 kg mass located at the origin? 3.0 x 10° kg 2.0 x 103 m 7.5 x 10° kg 1.2 x 10° kg 5.0 x 103 m

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### Problem Statement

Two masses, one \(7.5 \times 10^9 \, \text{kg}\) and the other \(3.0 \times 10^9 \, \text{kg}\), are placed along the x and y axes respectively as shown in the figure below. What is the net gravitational force (magnitude and angle from x-axis) on the \(1.2 \times 10^9 \, \text{kg}\) mass located at the origin?

### Diagram Description

The diagram shows a coordinate system with:

- A mass of \(1.2 \times 10^9 \, \text{kg}\) located at the origin (0,0).
- A mass of \(7.5 \times 10^9 \, \text{kg}\) placed on the x-axis at a distance of \(5.0 \times 10^3 \, \text{m}\) from the origin.
- A mass of \(3.0 \times 10^9 \, \text{kg}\) placed on the y-axis at a distance of \(2.0 \times 10^3 \, \text{m}\) from the origin.

The x and y axes are marked as \(\hat{x}\) and \(\hat{y}\) respectively.

### Explanation

To solve the problem, you need to calculate the gravitational force exerted on the \(1.2 \times 10^9 \, \text{kg}\) mass by the other two masses and then find the net force:

1. **Calculate the Force from Each Mass:**
   - Use Newton's law of universal gravitation: \( F = \frac{G \cdot m_1 \cdot m_2}{r^2} \)
   - Calculate \( F_{x} \) from the \(7.5 \times 10^9 \, \text{kg}\) mass.
   - Calculate \( F_{y} \) from the \(3.0 \times 10^9 \, \text{kg}\) mass.

2. **Determine the Net Force:**
   - Find the vector sum of \( F_{x} \) and \( F_{y} \) to get the net force.
   - Use trigonometry to determine the angle from the x-axis.

This calculation will give you the magnitude and direction
Transcribed Image Text:### Problem Statement Two masses, one \(7.5 \times 10^9 \, \text{kg}\) and the other \(3.0 \times 10^9 \, \text{kg}\), are placed along the x and y axes respectively as shown in the figure below. What is the net gravitational force (magnitude and angle from x-axis) on the \(1.2 \times 10^9 \, \text{kg}\) mass located at the origin? ### Diagram Description The diagram shows a coordinate system with: - A mass of \(1.2 \times 10^9 \, \text{kg}\) located at the origin (0,0). - A mass of \(7.5 \times 10^9 \, \text{kg}\) placed on the x-axis at a distance of \(5.0 \times 10^3 \, \text{m}\) from the origin. - A mass of \(3.0 \times 10^9 \, \text{kg}\) placed on the y-axis at a distance of \(2.0 \times 10^3 \, \text{m}\) from the origin. The x and y axes are marked as \(\hat{x}\) and \(\hat{y}\) respectively. ### Explanation To solve the problem, you need to calculate the gravitational force exerted on the \(1.2 \times 10^9 \, \text{kg}\) mass by the other two masses and then find the net force: 1. **Calculate the Force from Each Mass:** - Use Newton's law of universal gravitation: \( F = \frac{G \cdot m_1 \cdot m_2}{r^2} \) - Calculate \( F_{x} \) from the \(7.5 \times 10^9 \, \text{kg}\) mass. - Calculate \( F_{y} \) from the \(3.0 \times 10^9 \, \text{kg}\) mass. 2. **Determine the Net Force:** - Find the vector sum of \( F_{x} \) and \( F_{y} \) to get the net force. - Use trigonometry to determine the angle from the x-axis. This calculation will give you the magnitude and direction
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