A 100 kg person and their 12 kg dog are 7.5 m away from each other. If you approximate them both as perfectly spherical what if the attractive gravitational force between them? Use G = 6.67×10-11 N.m²/kg² Enter to 3 significant figures 3.56 X10 √ N F grav
A 100 kg person and their 12 kg dog are 7.5 m away from each other. If you approximate them both as perfectly spherical what if the attractive gravitational force between them? Use G = 6.67×10-11 N.m²/kg² Enter to 3 significant figures 3.56 X10 √ N F grav
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Gravitational Force Calculation Example**
**Problem:**
A 100 kg person and their 12 kg dog are 7.5 m away from each other. If you approximate them both as perfectly spherical, what is the attractive gravitational force between them?
**Given:**
- Mass of the person (m₁) = 100 kg
- Mass of the dog (m₂) = 12 kg
- Distance between them (r) = 7.5 m
Use the gravitational constant:
\[ G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 \]
**Formula:**
The gravitational force (\( F_{\text{grav}} \)) is calculated using Newton's law of universal gravitation:
\[ F_{\text{grav}} = \frac{G \cdot m_1 \cdot m_2}{r^2} \]
**Solution:**
Enter to 3 significant figures:
\[ F_{\text{grav}} = 3.56 \times 10^{-7} \, \text{N} \]
(A box with a red symbol indicates an incorrect solution or input is present, suggesting that the calculated or entered value could be revisited for accuracy.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5a3df371-d475-482a-84ce-057c931f1fc6%2Fa7195945-44a7-4e1d-bda8-48ee7f61798c%2F0d6be4l_processed.png&w=3840&q=75)
Transcribed Image Text:**Gravitational Force Calculation Example**
**Problem:**
A 100 kg person and their 12 kg dog are 7.5 m away from each other. If you approximate them both as perfectly spherical, what is the attractive gravitational force between them?
**Given:**
- Mass of the person (m₁) = 100 kg
- Mass of the dog (m₂) = 12 kg
- Distance between them (r) = 7.5 m
Use the gravitational constant:
\[ G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 \]
**Formula:**
The gravitational force (\( F_{\text{grav}} \)) is calculated using Newton's law of universal gravitation:
\[ F_{\text{grav}} = \frac{G \cdot m_1 \cdot m_2}{r^2} \]
**Solution:**
Enter to 3 significant figures:
\[ F_{\text{grav}} = 3.56 \times 10^{-7} \, \text{N} \]
(A box with a red symbol indicates an incorrect solution or input is present, suggesting that the calculated or entered value could be revisited for accuracy.)
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