A 100 kg person and their 12 kg dog are 7.5 m away from each other. If you approximate them both as perfectly spherical what if the attractive gravitational force between them? Use G = 6.67×10-11 N.m²/kg² Enter to 3 significant figures 3.56 X10 √ N F grav

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**Gravitational Force Calculation Example**

**Problem:**
A 100 kg person and their 12 kg dog are 7.5 m away from each other. If you approximate them both as perfectly spherical, what is the attractive gravitational force between them?

**Given:**
- Mass of the person (m₁) = 100 kg
- Mass of the dog (m₂) = 12 kg
- Distance between them (r) = 7.5 m

Use the gravitational constant:
\[ G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 \]

**Formula:**
The gravitational force (\( F_{\text{grav}} \)) is calculated using Newton's law of universal gravitation:
\[ F_{\text{grav}} = \frac{G \cdot m_1 \cdot m_2}{r^2} \]

**Solution:**
Enter to 3 significant figures:
\[ F_{\text{grav}} = 3.56 \times 10^{-7} \, \text{N} \]

(A box with a red symbol indicates an incorrect solution or input is present, suggesting that the calculated or entered value could be revisited for accuracy.)
Transcribed Image Text:**Gravitational Force Calculation Example** **Problem:** A 100 kg person and their 12 kg dog are 7.5 m away from each other. If you approximate them both as perfectly spherical, what is the attractive gravitational force between them? **Given:** - Mass of the person (m₁) = 100 kg - Mass of the dog (m₂) = 12 kg - Distance between them (r) = 7.5 m Use the gravitational constant: \[ G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 \] **Formula:** The gravitational force (\( F_{\text{grav}} \)) is calculated using Newton's law of universal gravitation: \[ F_{\text{grav}} = \frac{G \cdot m_1 \cdot m_2}{r^2} \] **Solution:** Enter to 3 significant figures: \[ F_{\text{grav}} = 3.56 \times 10^{-7} \, \text{N} \] (A box with a red symbol indicates an incorrect solution or input is present, suggesting that the calculated or entered value could be revisited for accuracy.)
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