7.34 Suppose that the electricity in your home has g out on a hot, humid summer day and the power company will not be able to fix the problem for s days. The freezer in the basement contains $300 worth of food that you cannot afford to let spoil. You would also like to keep one window air conditioner running, as well as run the refrigerator in your kitchen. When these appliances are on, they draw the following currents (all values are rms): gone several 9.6 A rms @ 120 V rms Air conditioner: pf = 0.90 lagging Freezer: 4.2 A rms @ 120 V rms pf = 0.87 lagging Refrigerator: 3.5 A rms @ 120 V rms pf = 0.80 lagging In the worst-case scenario, how much power must an emergency generator supply?

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### Scenario 7.34: Power Supply Calculations

Suppose that the electricity in your home has gone out on a hot, humid summer day, and the power company will not be able to fix the problem for several days. The freezer in the basement contains $300 worth of food that you cannot afford to let spoil. You would also like to keep one window air conditioner running, as well as run the refrigerator in your kitchen. When these appliances are on, they draw the following currents (all values are RMS, or root mean square):

- **Air Conditioner:**
  - Current: 9.6 A rms at 120 V rms
  - Power factor (pf): 0.90 lagging

- **Freezer:**
  - Current: 4.2 A rms at 120 V rms
  - Power factor (pf): 0.87 lagging

- **Refrigerator:**
  - Current: 3.5 A rms at 120 V rms
  - Power factor (pf): 0.80 lagging

**Problem:** In the worst-case scenario, how much power must an emergency generator supply?

### Analysis and Explanation:

To determine how much power the emergency generator must supply, you need to calculate the real power consumed by each appliance and sum them up.

1. **Real Power Calculation**: Real power (P) is calculated using the formula:
   \[
   P = VI \times \text{pf}
   \]
   where V is the voltage, I is the current, and pf is the power factor.

2. **For Each Appliance**:
   - **Air Conditioner**:
     \[
     P = 120 \, \text{V} \times 9.6 \, \text{A} \times 0.90 = 1036.8 \, \text{W}
     \]
   - **Freezer**:
     \[
     P = 120 \, \text{V} \times 4.2 \, \text{A} \times 0.87 = 438.48 \, \text{W}
     \]
   - **Refrigerator**:
     \[
     P = 120 \, \text{V} \times 3.5 \, \text{A} \times 0.80 = 336 \, \text{W}
     \]
Transcribed Image Text:### Scenario 7.34: Power Supply Calculations Suppose that the electricity in your home has gone out on a hot, humid summer day, and the power company will not be able to fix the problem for several days. The freezer in the basement contains $300 worth of food that you cannot afford to let spoil. You would also like to keep one window air conditioner running, as well as run the refrigerator in your kitchen. When these appliances are on, they draw the following currents (all values are RMS, or root mean square): - **Air Conditioner:** - Current: 9.6 A rms at 120 V rms - Power factor (pf): 0.90 lagging - **Freezer:** - Current: 4.2 A rms at 120 V rms - Power factor (pf): 0.87 lagging - **Refrigerator:** - Current: 3.5 A rms at 120 V rms - Power factor (pf): 0.80 lagging **Problem:** In the worst-case scenario, how much power must an emergency generator supply? ### Analysis and Explanation: To determine how much power the emergency generator must supply, you need to calculate the real power consumed by each appliance and sum them up. 1. **Real Power Calculation**: Real power (P) is calculated using the formula: \[ P = VI \times \text{pf} \] where V is the voltage, I is the current, and pf is the power factor. 2. **For Each Appliance**: - **Air Conditioner**: \[ P = 120 \, \text{V} \times 9.6 \, \text{A} \times 0.90 = 1036.8 \, \text{W} \] - **Freezer**: \[ P = 120 \, \text{V} \times 4.2 \, \text{A} \times 0.87 = 438.48 \, \text{W} \] - **Refrigerator**: \[ P = 120 \, \text{V} \times 3.5 \, \text{A} \times 0.80 = 336 \, \text{W} \]
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