7.30 There are two possible products in the electrophilic addition step shown here. Draw both possible products and predict which one is more stable. Br

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Explain Please, Thank You: There are two possible products in the electrophillic addition step shown here. Draw both possible products and predict which one is more stable. 

**Exercise 7.30: Electrophilic Addition Reaction**

There are two possible products in the electrophilic addition step shown here. Draw both possible products and predict which one is more stable.

**Diagram Explanation:**
The diagram illustrates an electrophilic addition reaction. It shows a molecule with a double bond (alkene) interacting with a hydrogen bromide (HBr) molecule. Arrows indicate the movement of electrons during the reaction.

- The first arrow starts from the double bond, pointing towards the hydrogen (H) atom in HBr, indicating that the pi electrons from the double bond will form a bond with hydrogen.
- The second arrow starts from the bond between H and Br, pointing towards the bromine (Br) atom, suggesting that the Br will gain the electrons and become a bromide ion (Br⁻).

Students are encouraged to use this information to draw the two possible products formed after this electrophilic addition and determine which one is more stable based on the structure and stability principles of carbocations.
Transcribed Image Text:**Exercise 7.30: Electrophilic Addition Reaction** There are two possible products in the electrophilic addition step shown here. Draw both possible products and predict which one is more stable. **Diagram Explanation:** The diagram illustrates an electrophilic addition reaction. It shows a molecule with a double bond (alkene) interacting with a hydrogen bromide (HBr) molecule. Arrows indicate the movement of electrons during the reaction. - The first arrow starts from the double bond, pointing towards the hydrogen (H) atom in HBr, indicating that the pi electrons from the double bond will form a bond with hydrogen. - The second arrow starts from the bond between H and Br, pointing towards the bromine (Br) atom, suggesting that the Br will gain the electrons and become a bromide ion (Br⁻). Students are encouraged to use this information to draw the two possible products formed after this electrophilic addition and determine which one is more stable based on the structure and stability principles of carbocations.
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