7.3.5Question HelpDo one of the following, as appropriate. (a) Find the critical value za/2, (b) find the critical value t/2: (c) state that neither the normal nor the tdistribution applies.Confidence level 90%; n= 16; o is known; population appears to be very skewed.Click here to view a table of critical t-values.Click here to view page 1 of the standard normal table.Click here to view page 2 of the standard normal table.Find the critical value.O A. ta/2 = 1.753O B. ta/2 = 1.341O C. za/2 = 1.645%3DO D. Za/2 = 1.28%3DO E. Neither normal nor t distribution applies. t distribution: Critical t valuesArea in One Tail0.0050.010.0250.050.10Degrees ofArea in Two TailsFreedom0.010.020.050.100.2063.65731.82112.7066.3143.0781.8869.9255.8414.6044.0323.7076.9654.3032.9204.5413.1822.7762.3531.6383.7472.1321.5333.3652.5712.0151.4763.1432.4471.9431.4403.4992.9982.3651.8951.4153.3553.2502.8962.3062.2621.8601.3972.8212.7641.8331.3833.1693.106101.8122.2282.2011.372112.7181.7961.363123.0552.6812.1791.7821.356133.0122.6502.1601.7711.350

It can not be a t test because t -test assumes that the data is distributed normally. It cannot be a…

Answered: 7.3.5 Question Help Do one of the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Determine the t-value in each of the cases. i Table of t-Distribution Areas Click the icon to view the table of areas under the t-distribution. (a) Find the t-value such that the area in the right tail is 0.05 with 12 degrees of freedom. 1.782 (Round to three decimal places as needed.) (b) Find the t-value such that the area in the right tail is 0.25 with 5 degrees of freedom. 0.727 (Round to three decimal places as needed.) -Area in (c) Find the t-value such that the area left of the t-value is 0.01 with 26 degrees of freedom. [Hint right tail - 2.479 (Round to three decimal places as needed.) (d) Find the critical t-value that corresponds to 95% confidence. Assume 10 degrees of freedom. Table VI (Round to three decimal places as needed.) t-Distribution Area in Right Tail df 0.25 0.20 0.15 0.10 0.05 0.025 0.02 0.01 0.005 0.0025 0.001 0.0005 127.321 14.089 636.619 31.599 12.924 8.610 6.869 1 1.376 1.963 3.078 6.314 12.706 4.303 3.182 2.776 2.571 15.894 31.821 63.657 9.925 5.841 4.604…
Question Find the area to the right of the z-score -1.90 under the standard normal curve. Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -2.1 0.0179 0.0174 0.0170 0.0166 0.0162 0.0158 0.0154 0.0150 0.0146 0.0143 -2.0 0.0228 0.0222 0.0217 0.0212 0.0207 0.0202 0.0197 0.0192 0.0188 0.0183 -1.9 0.0287 0.0281 0.0274 0.0268 0.0262 0.0256 0.0250 0.0244 0.0239 0.0233 -1.8 0.0359 0.0351 0.0344 0.0336 0.0329 0.0322 0.0314 0.0307 0.0301 0.0294 Use the value(s) from the table above. Provide your answer below: FEEDBACK MORE INSTRUCTION SUBMIT Content attribution
Answe part d and e
A t distribution with 6 degrees of freedom is graphed below. The region under the curve to the right of t0.04 is shaded. The area of this region is 0.04. 10.04= 0.4- x 0.3 Area = 0.04 I ¹0.04 Find the value of 0.04. Round your answer to three decimal places. 0.2+ 0.1+
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Interstate Speeds It has been reported that the standard deviation of the speeds of drivers on Interstate 75 near Findlay, Ohio, is 8 miles per hour for all vehicles. A driver feels from experience that this is very low. A survey is conducted, and for 29 drivers the standard deviation is 9.1 miles per hour. At =α0.05, is the driver correct? Assume the variable is normally distributed. Critical Values____
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-3 -1 0 1 -2 2 3 Please show your answer to 2 decimal places. About % of the area under the curve of the standard normal distribution (u = 0 and o = 1) is outside the interval Z = (-0.51,0.51) (or beyond 0.51 standard deviations of the mean).
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1 Draw a graph and find the probability of a bone density test score greater than-1.85 Sketch the region. Choose the correct graph below od The probability is (Round to four decimal places as needed) -3.00 ody (EL) odb on A -125 odb
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Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. 2 The area of the shaded region is (Round to four decimal places as needed.) A W S X дв mand 3 8.0 E D C $ 4 R F % 5 V T G 6 MacBook Air B & Y H & 7 U N * 8 J DII 1 M ( 9 K DO O < дв I ) O L F10 P command Time Remaining: 01:47:15 Next - : ; FR { + [ z=-0.84 z=1.28 option ? 1 } 1 delete 0 r

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