7.2. An aluminum disc with a radius of 15 cm that is 0.50 cm thick will have a mass of about 950 g. Such a disc lies in the horizontal plane and is spinning at a rate of 30 RPM counterclockwise, as viewed from above. Calculate the following: (a) The rotational inertia of the disc. (b) The magnitude and direction of the angular momentum of the disc. (c) The rotational kinetic energy of the disc.

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Chapter1: Units, Trigonometry. And Vectors
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**7.1** A spaceship orbits the Moon in a circular orbit at an altitude of 25,000 m above the surface. Assuming it to be subject only to the gravitational pull of the Moon, find its speed and the time it takes for one orbit. (The mass of the Moon is \(7.34 \times 10^{22}\) kg, and its radius is \(1.74 \times 10^{6}\) m.)

**7.2** An aluminum disc with a radius of 15 cm that is 0.50 cm thick will have a mass of about 950 g. Such a disc lies in the horizontal plane and is spinning at a rate of 30 RPM counterclockwise, as viewed from above. Calculate the following:

(a) The rotational inertia of the disc.

(b) The magnitude and direction of the angular momentum of the disc.

(c) The rotational kinetic energy of the disc.
Transcribed Image Text:**7.1** A spaceship orbits the Moon in a circular orbit at an altitude of 25,000 m above the surface. Assuming it to be subject only to the gravitational pull of the Moon, find its speed and the time it takes for one orbit. (The mass of the Moon is \(7.34 \times 10^{22}\) kg, and its radius is \(1.74 \times 10^{6}\) m.) **7.2** An aluminum disc with a radius of 15 cm that is 0.50 cm thick will have a mass of about 950 g. Such a disc lies in the horizontal plane and is spinning at a rate of 30 RPM counterclockwise, as viewed from above. Calculate the following: (a) The rotational inertia of the disc. (b) The magnitude and direction of the angular momentum of the disc. (c) The rotational kinetic energy of the disc.
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