7.15 The transistor in the circuit of Fig. P7.15 is biased at a de collector current of 0.3 mA. What is the voltage gain? (Hint: Use Thévenin's theorem to convert the circuit to the form in Fig. 7.6.) +5 V 10 kΩ 10 kM
7.15 The transistor in the circuit of Fig. P7.15 is biased at a de collector current of 0.3 mA. What is the voltage gain? (Hint: Use Thévenin's theorem to convert the circuit to the form in Fig. 7.6.) +5 V 10 kΩ 10 kM
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Lq. (7.11). DIIOW Ulat nc gamm CAPITSSION Cllangts to
(g) A,
-500 V/V, P = 2.0 V
=
-I RV,
(Vcc – Vee) /Vr
7.15 The transistor in the circuit of Fig. P7.15 is biased at
А,
IR.
1+
Vcc – VCE
1+
a de collector current of 0.3 mA. What is the voltage gain?
(Hint: Use Thévenin's theorem to convert the circuit to the
form in Fig. 7.6.)
V+VCE -
VA+VCE
А
For the case Vcc = 5 V and VCE = 3 V, what is the gain
without and with the Early effect taken into account?
+5 V
Let V, = 100 V.
7.18 When the amplifier circuit of Fig. 7.6 is biased with a
certain VRF, the dc voltage at the collector is found to be +2 V.
For Vcc =+5 V and R. =1 k2, find I, and the small-signal
voltage gain. For a change AV BE
10 kΩ
BE >
O Vo
CC
+5 mV, calculate the
resulting Avo. Calculate it two ways: by using the transistor
exponential characteristic Aic, and approximately, using
the small-signal voltage gain. Repeat for AvBE =
10 kΩ
= -5 mV.
-
Summarize your results in a table.
Figure PZ.15
*7.19 Consider the amplifier circuit of Fig. 7.6 when oper-
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Lq. (7.11). DIIOW Ulat nc gamm CAPITSSION Cllangts to
(g) A,
-500 V/V, P = 2.0 V
=
-I RV,
(Vcc – Vee) /Vr
7.15 The transistor in the circuit of Fig. P7.15 is biased at
А,
IR.
1+
Vcc – VCE
1+
a de collector current of 0.3 mA. What is the voltage gain?
(Hint: Use Thévenin's theorem to convert the circuit to the
form in Fig. 7.6.)
V+VCE -
VA+VCE
А
For the case Vcc = 5 V and VCE = 3 V, what is the gain
without and with the Early effect taken into account?
+5 V
Let V, = 100 V.
7.18 When the amplifier circuit of Fig. 7.6 is biased with a
certain VRF, the dc voltage at the collector is found to be +2 V.
For Vcc =+5 V and R. =1 k2, find I, and the small-signal
voltage gain. For a change AV BE
10 kΩ
BE >
O Vo
CC
+5 mV, calculate the
resulting Avo. Calculate it two ways: by using the transistor
exponential characteristic Aic, and approximately, using
the small-signal voltage gain. Repeat for AvBE =
10 kΩ
= -5 mV.
-
Summarize your results in a table.
Figure PZ.15
*7.19 Consider the amplifier circuit of Fig. 7.6 when oper-
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Microelectronic_Circuits_...
Rc
+
UCE
Figure 7.6 BJT amplifier biased at a point
voltage signal v superimposed on the de bias voltage VRp:
The resulting output signal v appears superimposed on the de
collector voltage Ver: The amplitude of v, is larger than that of
v, by the voltage gain A,.
with a small
Upe
BE
UBE
V BE
CE *
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Microelectronic_Circuits_...
Rc
+
UCE
Figure 7.6 BJT amplifier biased at a point
voltage signal v superimposed on the de bias voltage VRp:
The resulting output signal v appears superimposed on the de
collector voltage Ver: The amplitude of v, is larger than that of
v, by the voltage gain A,.
with a small
Upe
BE
UBE
V BE
CE *
11 ( 377 (406 / 1489)
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